C is the only one that makes sense to me try and let me know
Answer:
495 combinations of 4 students can be selected.
Step-by-step explanation:
The order of the students in the sample is not important. So we use the combinations formula to solve this question.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.
How many combination of random samples of 4 students can be selected?
4 from a set of 12. So
495 combinations of 4 students can be selected.
5^5-9(200/4)-(10*90)/5-4^4(5)+156-256
= 3125-9( 200/4)-(10*90)/5-(4^4)(5)+156-256
= 3125-(9)(50)- (10*90)/5-(4^4)(5)+156-256
= 3125-450- (10*90)/5-(4^4)(5)+156-256
= 2675-(10*90)/5-(4^4)(5)+156-256
= 2675 - 900/5 - (4^4)(5)+156-256
= 2675 - 180 - (4^4)(5)+156-256
= 2495 - (4^4)(5)+156-256
= 2495 - 1280 + 156 -256
= 1215 + 156 - 256
= 1371 - 256
= 1115
I hope that's help , please if you have question(s) just let me know !
8(x - 6) = 4x
Distribute.
8x - 48 = 4x
Subtract 8x from both sides.
8x -8x - 48 =4x -8x
Now you have...
-48 = -4x
Divide -4 by both sides.
-48/-4 = -4x/-4
12 = x
The number is 12.
