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luda_lava [24]
3 years ago
8

Need help finding a constant k at which the function is continuous everywhere.

Mathematics
2 answers:
RSB [31]3 years ago
6 0

Answer: 36k = k - 6, k = -6/35


Step-by-step explanation:

The two parts are continuous by themselves. If either weren't, no value of k could fix it.


The only point of discontinuity is x=-6. The function will be continuous for any and all values of k which make k(-6)^2 = -6+k. 36k = k-6, 35k=-6, k=-6/35.

saveliy_v [14]3 years ago
3 0

Answer:

k = -6/35

Step-by-step explanation:

To make the function continuous

kx^2 = x+k

These must be equal where the function is defined for two different intervals

This is at the point x=-6  so let x=-6

k(-6)^2 = -6+k

36k = -6+k

Subtract k from each side

36k-k = -6+k-k

35k = -6

Divide by 35

35k/35 = -6/35

k = -6/35


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What is x^2+x-20=0. <br> please help
zepelin [54]
X² + x - 20 = 0

x² = x * x
x = the sum of the factors of -20
-20 ⇒  1 x 20
            2 x 10
          - 4 x 5 ⇒ only these factors can arrive to a sum of 1

(x - 4)(x + 5) = x(x+5) - 4(x+5) = x² + 5x - 4x - 20 = x² + x - 20

x - 4 = 0
x = 4

x + 5 = 0
x = -5
7 0
4 years ago
Find the length of a line segment with endpoints of 19 and –39. A. –58 B. –20 C. 20 D. 58
Lisa [10]
19 - (-39) = 19 + 39 = 58

<span>length of a line segment is 58 units.</span>
5 0
3 years ago
Read 2 more answers
Explain why the simultaneous equations y = -2/3x + 4/3 and 12x + 18y = 24 have an infinite number of solutions. What can you ded
denpristay [2]

Answer:

It's the same equation

Step-by-step explanation:

12x+18y=24

y=(-12x+24)/18

y=-2/3x+4/3

The intersect is the solution, so there are infinitely many solutions

4 0
3 years ago
What is the equation of the line passing through the points (2, –1) and (5, –10) in slope-intercept form?
adoni [48]
(2,-1)(5,-10)
slope = (-10 - (-1) / (5 - 2) = -9/3 = -3

y = mx + b
slope(m) = -3
use either of ur points....(2,-1)...x = 2 and y = -1
now we sub and find b, the y int
-1 = -3(2) + b
-1 = -6 + b
-1 + 6 = b
5 = b

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4 0
3 years ago
Solve the system of linear equations and check any solution algebraically
Vedmedyk [2.9K]
It is pretty long, hope you understand 
  x+y+z=6
+
  2x-y+z=3
-------------
  3x+2z=9
->3x=9-2z (1)

3x-z=0
3x=z (2)

From (1)+(2)-> z=9-2z
solve for z
-3z=9
z=-3 (3)

plug (3) in (2)
->3x=-3
->x=-1 (4)

Plug (3) and (4) in <span>x+y+z=6
</span>-3+y+(-3)=6
solve for y
y-6=6
->y=12
Answer:
x=-1
y=12
z=-3


6 0
3 years ago
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