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Naily [24]
3 years ago
15

Which numbers are rational? 12 81, 50, -12, 0, 5 6.54

Mathematics
2 answers:
Akimi4 [234]3 years ago
7 0

I think the answer is -12

solmaris [256]3 years ago
4 0

Answer:

All are rational

Step-by-step explanation:

A rational number is a number that can be written as a fraction.

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The cheerleaders are making a banner that is 8 feet wide. The length of the banner is 1 1/3 times the width of the banner . How
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8 multiplied by 1 1/3 = 10.66 as fraction it’s = 10 2/3
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Which numbers round to 0.8 when rounded to the nearest tenth?
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E because, as it says "5 below, shove it below, 5 and up, shove it up"

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Please answer this correctly
jeka57 [31]

Answer:

The answer is B.

Step-by-step explanation:

We already know that there are 60 people in the orchestr, and we know 20 percent play cello. This mean that the second graph will help us figure out how many people play cello.

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3 years ago
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An atom has 24 protons and 12 neutrons what is the chemical symbol for the atom?
kykrilka [37]

<u>Answer:</u>

The element is Chromium.

<u>Explanation:</u>

The atom has 24 protons and 12 neutrons.

We know that Cr has 24 number of protons, to the Chemical is Cr (Chromium)

Again, we know that the atomic number is the number of protons and the atomic mass is the sum of proton and neutron.

So, the atomic number is 24 and the atomic mass is (24+12)= 36

Therefore, the symbol is \bold^{36} \mathrm{Cr}_{24}\bold

4 0
3 years ago
What is the probability that all the roots of x2 + bx + c = 0 are real? [0,1]?
notsponge [240]

x^2+bx+c will have real roots when the discriminant of the quadratic, \Delta=b^2-4c, is non-negative, i.e.

b^2-4c\ge0\implies b^2\ge4c

Your question about probability is currently impossible to answer without knowing exactly what the experiment is. Are you picking b,c at random from some interval? Is the choice of either distributed a certain way?

I'll assume the inclusion of "[0,1]" in your question is a suggestion that both b,c are chosen indepently of one another from [0, 1]. Let B,C denote the random variables that take on the values of b,c, respectively. I'll assume B,C are identical and follow the standard uniform distribution, i.e. they each have the same PDF and CDF as below:

f_X(x)=\begin{cases}1&\text{for }0

F_X(x)=\begin{cases}0&\text{for }x

where X is either of B,C.

Then the question is to find P(B^2\ge4C). We have

P(B^2\ge4C)=P\left(C\le\dfrac{B^2}4\right)

and we can condition the random variable C on the event of B=b by supposing

P\left(C\le\dfrac{B^2}4\right)=P\left(\left(C\le\dfrac{B^2}4\right)\land(B=b)\right)=P\left(C\le\dfrac{B^2}4\mid B=b\right)\cdot P(B=b)

then integrate over all possible values of b.

=\displaystyle\int_{-\infty}^\infty P\left(C\le\dfrac{b^2}4\right)f_B(b)\,\mathrm db

=\displaystyle\int_{-\infty}^\infty F_C\left(\dfrac{b^2}4\right)f_B(b)\,\mathrm db

=\displaystyle\int_0^1\dfrac{b^2}4\,\mathrm db=\frac1{12}

4 0
3 years ago
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