Answer:
Part a) The distance on a map between Joseph's house and the airport is 2.53 inches
Part b) The distance on a map between the airport and the restaurant is 1.68 inches and the total distance on a map between Joseph's house and the restaurant is 4.21 inches
Step-by-step explanation:
Part a) The actual distance between Joseph's house and the airport is 24 miles. How far apart are Joseph's house and the airport on the map?
we know that
The scale of a map is 1 inch : 9.5 miles
so
using proportion
Find the distance on a map if the actual distance between Joseph's house and the airport is 24 miles
Let
x-----> the distance on a map
1/9.5=x/24
x=24/9.5=2.53 inches
Part b) Joseph traveled from his house to the airport. He then traveled another 16 miles past the airport to a restaurant. How many inches on the map represent this distance?
we know that
The scale of a map is 1 inch : 9.5 miles
so
using proportion
Find the distance on a map if the actual distance between airport to the restaurant is 16 miles
Let
x-----> the distance on a map
1/9.5=x/16
x=16/9.5=1.68 inches
The total distance on a map between Joseph's house and the restaurant is equal to
2.53 inches+1.68 inches=4.21 inches
Answer:
Step-by-step explanation:
we are given half-life of PO-210 and the initial mass
we want to figure out the remaining mass <u>after</u><u> </u><u>4</u><u>2</u><u>0</u><u> </u><u>days</u><u> </u>
in order to solve so we can consider the half-life formula given by
where:
- f(t) is the remaining quantity of a substance after time t has elapsed.
- a is the initial quantity of this substance.
- T is the half-life
since it halves every 140 days our T is 140 and t is 420. as the initial mass of the sample is 5 our a is 5
thus substitute:
reduce fraction:
By using calculator we acquire:
hence, the remaining sample after 420 days is 0.625 kg
Having two opposite faces plane and parallel a plane-parallel sheet of glass.
Or ?? ⬇️
In geometry, parallel lines are lines in a plane which do not meet; that is, two straight lines in a plane that do not intersect at any point are said to be parallel. Colloquially, curves that do not touch each other or intersect and keep a fixed minimum distance are said to be parallel.
Answer:
Alright, so we have to find the LCM of 2.75 and 3.5.
A good start would be to multiply them together to get 9.625, but we want a whole day!
This would be every 77 days :)
Answer:
![X = \left[\begin{array}{cccc}12&-24&8&16\end{array}\right]](https://tex.z-dn.net/?f=X%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D12%26-24%268%2616%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
A matrix is given by
![A = \left[\begin{array}{cccc}6&-12&4&8\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D6%26-12%264%268%5Cend%7Barray%7D%5Cright%5D)
Now, we have to find the matrix X if 
⇒ X = 2A
Now, multiplication of a constant with a matrix means multiplication with that constant with all the terms of the matrix.
So, ![X = \left[\begin{array}{cccc}6 \times 2&-12 \times 2&4 \times 2&8 \times 2\end{array}\right]](https://tex.z-dn.net/?f=X%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D6%20%5Ctimes%202%26-12%20%5Ctimes%202%264%20%5Ctimes%202%268%20%5Ctimes%202%5Cend%7Barray%7D%5Cright%5D)
⇒ (Answer)
