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Firdavs [7]
3 years ago
9

You're using disk management to view primary and extended partitions on a suspect's drive. the program reports the extended part

ition's total size as larger than the sum of the sizes of logical partitions in this extended partition. what might you infer from this information?
Computers and Technology
1 answer:
kodGreya [7K]3 years ago
5 0

The best assumption to make is that there is a hidden partition and the drive needs to be further searched.

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Double any element's value that is less than controlValue. Ex: If controlValue = 10, then dataPoints = {2, 12, 9, 20} becomes {4
Aleksandr [31]

Answer:

import java.util.Scanner;

public class StudentScores

{

public static void main(String[] args) {

 Scanner scnr = new Scanner(System.in);

 final int NUM_POINTS = 4;

 int[] dataPoints = new int[NUM_POINTS];

 int controlValue;

 int i;

 controlValue = scnr.nextInt();

 for (i = 0; i < dataPoints.length; ++i) {

     dataPoints[i] = scnr.nextInt();

 }

 for (i = 0; i < dataPoints.length; ++i) {

     System.out.print(dataPoints[i] + " ");

 }

 System.out.println();

 for (i = 0; i < dataPoints.length; ++i) {

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     }

     System.out.print(dataPoints[i] + " ");

 }

}

}

Explanation:

*Added parts highligted.

After getting the control value and values for the array, you printed them.

Create a for loop that iterates through the dataPoints. Inside the loop, check if a value in dataPoints is smaller than the contorolValue. If it is, multiply that value with 2 and assign it to the dataPoints array. Print the elements of the dataPoints

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