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Nadusha1986 [10]
3 years ago
12

what is the result of dividing 48a^3 + 32a^2 + 16a by 4a? A. 12a^2 + 8a + 4 B. 12a^2 + 4a + 8 C. 12a + 8 D. 12a^2 + 4a + 4 Simpl

ify (2x-2y)(2y+8)=? A. 4xy-4y^2 B. 4xy-16x-4y^2-16y C. 4xy+16x-4y^2-16y D. 4xy+16x+4y^2+16y Simplify (-8q^3r^4s^2)^2=? A. 64q^9r^16s^4 B. -64q^6r^8s^4 C. 64q^6r^8s^4 D. -64q^9r^16s^4 What is the result if you divide -12x^8y^8 by 3x^4y^2? A. -4x^4y^6 B. 4x^2y^4 C. 4x^4y^6 D. -4x^2y^4
Mathematics
1 answer:
lora16 [44]3 years ago
6 0

Answer:

1. A. 12a^2 + 8a + 4

2. C. 4xy+16x-4y^2-16y

3. C. 64q^6r^8s^4

4. A. -4x^4y^6

Step-by-step explanation:

48a^3 + 32a^2 + 16a / 4a = (48a^3) / 4a + (32a^2) / 4a + (16a) / 4a = 12a^2 + 8a + 4.

So, the answer is A. 12a^2 + 8a + 4.

(2x-2y)(2y+8) = 4xy - 4y^2 + 16x -  16y.

So, the answer is C. 4xy+16x-4y^2-16y.

(-8q^3 * r^4 * s^2)^2 = (-8)^2 * q^6 * r^8 * s^4 = 64q^6r^8s^4.

So, the answer is C. 64q^6r^8s^4.

-12x^8y^8 / 3x^4y^2 = (-12 / 3) * (x^(8 - 4)) * (y^(8 - 2)) = -4x^4y^6.

So, the answer is A. -4x^4y^6.

Hope this helps!

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The denominator of a fraction is 10 more than its numerator.
Dennis_Churaev [7]

The right answer is Option C : 5

Step-by-step explanation:

Let,

The numerator of fraction = x

The denominator of a fraction is 10 more than its numerator.

\frac{x}{x+10}

When 1/3 is added to this fraction,

\frac{x}{x+10}+\frac{1}{3}

the resulting fraction’s denominator is three times the denominator of the original fraction its numerator is 15 less than its denominator

\frac{3(x+10)-15}{3(x+10)}

Therefore, it becomes

\frac{x}{x+10}+\frac{1}{3} = \frac{3(x+10)-15}{3(x+10)}

Taking LCM on left side

\frac{3x+(x+10)}{3(x+10)}=\frac{(3x+30)-15}{3(x+10)}\\\\\frac{3x+x+10}{3(x+10)}=\frac{3x+30-15}{x(x+10)}\\\\\frac{4x+10}{3(x+10)}=\frac{3x+15}{3(x+10)}

Multiplying both sides by 3(x+10)

3(x+10)*\frac{4x+10}{3(x+10)}=\frac{3x+15}{3(x+10)}*3(x+10)\\4x+10=3x+15\\4x-3x=15-10\\x=5

The numerator of original fraction is 5.

The right answer is Option C : 5

Keywords: fraction, addition

Learn more about fractions at:

  • brainly.com/question/11207748
  • brainly.com/question/11280112

#LearnwithBrainly

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