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1 year ago

Distributive property for x(11+2), please????

Mathematics

2 answers:

Hitman42 [59]1 year ago

6 0

Answer: 13x

Step-by-step explanation: Multiply x to 11 and 2

11x+2x=13x

Fynjy0 [20]1 year ago

6 0

X(11+2)= 13x because you have to distribute the x and i’ll give you 11x+2x and then you just add them together they both have x and get 13x.

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Given: Circumscribed polygon ELPJ

Katena32 [7]

Answer:

The perimeter of the polygon is $18\ units$

Step-by-step explanation:

we know that

In the given problem

If ELPJ is a circumscribed polygon and K, U, V, S are points of tangency

then

LK=LU

EK=ES

JS=JV

PU=PV

The perimeter of the polygon is equal to

$P=2(2+4+1+2)=18\ units$

6 0

2 years ago

It took a plane 2 hours to go from Dallas to NY with the head wind and 1.5 hours to get back with the tail wind. If the speed of

vladimir2022 [97]

Answer:

360 miles

Step-by-step explanation:

let speed of plane be x

speed of wind be c

Also note D = RT, where

D is distance and R is rate and T is time

For First Leg:

we can write:

(x - c) * 2 = D

2x - 2c = D

For Second Leg:

we can write:

(x+c)*1.5 = D

1.5x + 1.5c = D

We can equate and write:

2x - 2c = 1.5x + 1.5c

0.5x = 3.5c

We know Speed of Wind, c, is 30, so we have:

0.5x = 3.5(30)

0.5x = 105

x = 105/0.5 = 210 [speed of airplane]

We know distance is

D = 2x - 2c

D = 2(210) - 2(30)

D = 420 - 60

D = 360 miles

The distance is 360 miles

6 0

2 years ago

Find dy/dx given that y = sin x / 1 + cos x

kobusy [5.1K]

Answer:

$\frac{1}{1 + \cos(x) }$

Step-by-step explanation:

$y = \frac{ \sin(x) }{1 + \cos(x) }$

differentiating numerator wrt x :-

(sinx)' = cos x

differentiating denominator wrt x :- 

(1 + cos x)' = (cosx)' = - sinx

Let's say the denominator was "v" and the numerator was "u"

$(\frac{u}{v} )' = \frac{v. \: (u)' - u.(v)' }{ {v}^{2} }$

here,

since u is the numerator u= sinx and u = cos x
v(denominator) = 1 + cos x; v' = - sinx

$= \frac{((1 + \cos \: x) \cos \: x )- (\sin \: x. ( - \sin \: x) ) }{( {1 + \cos(x)) }^{2} }$

$= \frac{ \cos(x) + \cos {}^{2} (x) + \sin {}^{2} (x) }{(1 + \cos \: x) {}^{2} }$

since cos²x + sin²x = 1

$= \frac{ \cos \: x + 1}{(1 + \cos \: x) {}^{2} }$

diving numerator and denominator by 1 + cos x

$= \frac{1}{1 + \cos(x) }$

6 0

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