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vodomira [7]
3 years ago
10

How was the clean air act of 1970 different from previous legislation aimed at reducing pollution?

Biology
1 answer:
Ede4ka [16]3 years ago
8 0

Answer: B

Explanation:

I just did it

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You are working in a molecular biology lab and, unbeknownst to you, your lab partner left the foreign genomic DNA you are planni
fredd [130]

Answer:

B There will be blue colonies only

Explanation:

This screen in called the blue white screening.  This is a rapid test that allows scientist to check for their insert of choice in the colonies at a glance. The concept is that where the insert is located the <em>lac Z </em>gene in the vector is interrupted and therefor Xgal, a reporter can be produced. Where there are blue colonies being formed the plasmid has self-ligated and the <em>lac Z</em> gene is not interrupted and the X-gal can be formed rendering a blue color.

8 0
2 years ago
Which characteristics is common to all three groups of reptiles?
Flura [38]

They are ectotherms.

hope it is helpful to you

7 0
3 years ago
Read 2 more answers
In the Calvin cycle more atp than nadph is used how is this difference made up
Veseljchak [2.6K]

Answer:

Explanation:

The detailed description of photosynthesis is that chlorophyll a becomes oxidized chlorophyll a after being irradiated, and the water in the thylakoid is oxidized by oxidized chlorophyll a to form oxygen and hydrogen ions, and hydrogen ions pass through the class. The ATP synthase on the capsule membrane passes through the membrane into the chloroplast matrix, where it provides a certain chemical potential (ie, an energy produced from a high concentration to a low concentration), and then ADP and Pi on the membrane. Will get energy to form ATP; and NADPH+ is the front chlorophyll a is oxidized by light to release high-energy electrons e, e will be transferred to NADP+ (oxidized coenzyme II), the photolysis of the front water does not produce hydrogen ions? This led to the combination of NADP and H+, which became NADPH.

Next, their use, in front of the photoreaction, in the dark reaction, CO2 will react with the five-carbon compound in the chloroplast matrix, fixed to the formation of a three-carbon compound (one C in CO2, five C in five-carbon compound, Two three-carbon compounds are formed, and then ATP and NADPH supply hydrogen, respectively, and then return to ADP+Pi and NADP+, and the reduced three-carbon compound becomes organic (mostly sugar) and becomes The five-carbon compound will react with CO2 again, which is the Calvin cycle.

<em>Genetic mutation is an important factor that contributes to the pathogenesis and development of Alzheimer’s disease (AD). The genetic factors studied include the dominant mutations of genes encoding amyloid-β precursor protein (APP), presenilin 1 (PSEN1), and presenilin 2 (PSEN2). Additionally, more and more genes have been found to be potentially associated with AD, such as apolipoprotein E (APOE), glycogen synthase kinase 3 beta (GSK3B), dual specificity tyrosine-phosphorylation-regulated kinase 1A (DYRK1A), and Tau. Although many studies on the treatment of AD have not been successful, gene therapy is still considered as a potential way against AD, and some gene-therapy-based therapeutics have entered the clinical trial stage. Existing strategies for gene therapy against AD include gene inactivation, genetic modification, and immunoregulation, etc.</em>

<em>https://www.creativebiomart.net/alzheimacy/therapeutics/gene-therapy/</em>

8 0
2 years ago
In 1980, Y. published an extended pedigree of family in which
nydimaria [60]

Answer:

Zero (0)

Explanation:

According to the given information the genotype of the woman with blood type "AB" would by I^AI^B. The genotype of the man with blood type O would be "ii". Here, the alleles I^A and I^B are dominant over the allele "i".

A cross between parents with genotype I^AI^B and ii would give 50% of children with I^Ai genotype and 50% of children with I^Bi genotype. The children with "I^Ai genotype" would have blood type "A" and the children with I^Bi genotype would have blood type "B". This couple is never likely to have any child with blood type "O" since the mother does not carry allele "i".

Cross: I^AI^B x ii = 1/2 I^Ai : 1/2 I^Bi

5 0
3 years ago
In the protein synthesis STEM case, which of the following mutations/errors created
g100num [7]

Answer:

B. Premature stop codon mutation

Explanation:

5 0
2 years ago
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