I think the answer is D not sure though
25.71/(2.3*4.01*1.82) = 1.5316gcm^-3
Answer:
Thallium absorbed 1069.645 J heat to reach to its melting point.
Explanation:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Given data:
Mass of thallium = 32.9 g
specific heat capacity of thallium = 0.128 j/g. °C
Initial temperature = 49 °C
Final temperature = 303 °C
Solution:
Change in temperature = T₂- T₁
ΔT = 303 °C - 49 °C = 254 °C
Formula:
Q = m.c. ΔT
Q = 32.9 g ×0.128 j/g. °C × 254 °C
Q = 1069.645 J
Thallium absorbed 1069.645 J heat to reach to its melting point.
Waters freezing point in Celsius is 0 and 273.15 Kelvin (or 273 rounded to a whole number.
Answer:
Respiratory System:
Pathway of air: nasal cavities (or oral cavity) > pharynx > trachea > primary bronchi (right & left) > secondary bronchi > tertiary bronchi > bronchioles > alveoli (site of gas exchange)