Answer:
Step 1 H2 + 2 NO → N2O + H2O (slow)
step 2 N2O + H2 → N2 + H2O (fast)
Explanation:
It is known that the slowest step in a reaction is the rate determining step in a sequence of reactions (reaction mechanism).
We have two important pieces of information in the question to guide our decision making process.
The overall reaction equation, and the rate expression. The two;
2 H2 + 2 NO → N2 + 2 H2O and rate = k[H2][NO]2 all support the answer given above.
The number of electrons it take to fill the mos formed from the combination of the 3s orbitals of two atoms simply is 14 electrons.
<h3>How electrons are distributed in the 3s orbitals.</h3>
The 3s orbital possess two different spherical nodes which is highly connected with the principal quantum number. In order words, it has 2 radial nodes. Also the shape of the 3s orbital is spherical in shape.
That being said, from the context of the above given task, the number of electrons which fill the mos formed from the combination of the 3s orbitals of two atoms is fourteen electrons.
However, the electron configuration of an atom simply is the arrangement of electrons in the electron shell or orbit of the atom of that element.
In conclusion, it can be deduced from above s orbital has a maximum of two electrons and this energy increases as the orbitals increases.
Read more on electron:
brainly.com/question/860094
#SPJ1
RIVER CAPTURE. *is when the powerful and energetic river cuts back through watershed by headward erosion cupturing another river's water. CONDITION FOR RIVER CAPTURE TO OCCUR. * steeper gradient on the energetic stream side of the watershed.Apr 6, 2019
Answer:
34.2 g is the mass of carbon dioxide gas one have in the container.
Explanation:
Moles of
:-
Mass = 49.8 g
Molar mass of oxygen gas = 32 g/mol
The formula for the calculation of moles is shown below:
Thus,

Since pressure and volume are constant, we can use the Avogadro's law as:-
Given ,
V₂ is twice the volume of V₁
V₂ = 2V₁
n₁ = ?
n₂ = 1.55625 mol
Using above equation as:
n₁ = 0.778125 moles
Moles of carbon dioxide = 0.778125 moles
Molar mass of
= 44.0 g/mol
Mass of
= Moles × Molar mass = 0.778125 × 44.0 g = 34.2 g
<u>34.2 g is the mass of carbon dioxide gas one have in the container.</u>