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liq [111]
3 years ago
13

The water lattice: a. is formed from hydrophobic bonds. b. causes ice to be denser than water. c. causes water to have a relativ

ely low specific heat. d. excludes nonpolar substances. e. is held together by hydrogen bonds that are permanent; that is, they never break and reform.
Chemistry
1 answer:
Alexus [3.1K]3 years ago
7 0

Answer: Option (d) is the correct answer.

Explanation:

It is known that water loving bonds are called hydrophilic bonds and water hating bonds are called hydrophobic bonds. Since, water is a polar solvent and it is only able to dissolve polar molecules and not non-polar molecules.

Lattice of water and hydrogen bonding are responsible for the various properties of water like cohesion, adhesion, heat of vaporization etc.

Thus, we can conclude that water lattice excludes non-polar substances.

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3 years ago
Need help please help me
Mademuasel [1]

Answer:

The answer is most likely compound a

Explanation:

Covalent compounds have low melting and boiling points and conduct electricity poorly

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What is one benefit and one limitation of comparative investigations
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3 years ago
To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple _______. Then, plot ln(K
Aloiza [94]

Answer:

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us use the thermodynamic definition of the Gibbs free energy and its relationship with Ksp as follows:

\Delta G=-RTln(Ksp)\\\\\Delta G=\Delta H-T\Delta S

Thus, by combining them, we obtain:

-RTln(Ksp)=\Delta H-T\Delta S\\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{T\Delta S}{RT} \\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{\Delta S}{R}

Which is related to the general line equation:

y=mx+b

Whereas:

y=ln(Ksp)\\\\m=-\frac{\Delta H}{R} \\\\x=\frac{1}{T} \\\\b=\frac{\Delta S}{R}

It means that we answer to the blanks as follows:

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.

Regards!

8 0
3 years ago
What is the correct formula for Tin (IV) chromate nonahydrate?
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Answer:

Sn(CrO4)2 or Cr2O8Sn

Explanation:

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3 years ago
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