I’m struggling with this please I need the answer

Hurry please!! Use any model you choose to solve the story problem. Zoey found that box of dog food was left in the pantry. She

alexira [117]

<span>There is a box that is full which is 100% so if she is splitting the box equally she will be giving each dog 25% of the box or 1/4 of the box.</span>

7 0

3 years ago

What are the soltions to the innequality -7x+14 is grater than -3x-6

hichkok12 [17]

-7x+14>-3x-6

Add 3x to both sides

-7x+14+3x>-3x-6+3x

-4x+14>-6

Subtract 14 from both sides

-4x+14-14>-6-14

-4x>-20

Divide both sides by -4

-4x/4>-20/-4

x<5

I hope that's help , please let me know !

7 0

3 years ago

An arc with a measure of 190° has an arc length of 40<img src="https://tex.z-dn.net/?f=%5Cpi" id="TexFormula1" title="\pi" alt="

Anna007 [38]

Answer:

37.9 cm

Step-by-step explanation:

Arc length is:

s = 2πr (θ/360°)

where r is the radius and θ is the arc angle.

40π cm = 2πr (190°/360°)

20 cm = r (190°/360°)

r = 37.9 cm

4 0

4 years ago

Read 2 more answers

Let j = 32. What is the value of j + 12? A. 12 B. 20 C. 44 D. 50

Travka [436]

The answer ic C 44 yep

5 0

4 years ago

Read 2 more answers

A hypothesis test is conducted with a significance level of 10%. The alternative hypothesis states that more than 15% of a popul

Drupady [299]

Answer:

D. We cannot conclude that more than 15% of the population has at least one sibling.

Step-by-step explanation:

Data given and notation

n represent the random sample taken

X represent the number of people who has at least one sibling

$\hat p$ estimated proportion of people who has at least one sibling

$p_o=0.15$ is the value that we want to test

$\alpha=0.1$ represent the significance level

Confidence=90% or 0.90

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of people who has at least one sibling is more than 0.15:

Null hypothesis: $p\leq 0.15$

Alternative hypothesis: $p > 0.15$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Let's assume that the calculated value for this case is $z_{calc}$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.1$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z> z_{calc})=0.27$

So the p value obtained was a very high value and using the significance level given $\alpha=0.1$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 10% of significance the proportion of people who has at least one sibling is not significanlty higher than 0.15.

So then the best answer for this case would be:

D. We cannot conclude that more than 15% of the population has at least one sibling.

6 0

3 years ago