The extreme values of the function f(x) = x - 4sqrt(x) occur at the values of x for which f'(x) = 0
f'(x) = 1 - 2/sqrt(x) = 0
sqrt(x) - 2 = 0
sqrt(x) = 2
x = 4
To check for minimum or maximum,
f''(x) = 1/(sqrt(x))^3 = 1/(sqrt(4))^3 = 1/(2^3) = 1/8 => the point is a minimum.
Therefore, the minimum value = f(4) = 4 - 4sqrt(4) = 4 - 4(2) = 4 - 8 = -4 and occurs at x = 4.
Answer:
first one is correct................
In this specific case, the <em>initial term</em> (a) is 5 and the <em>common ratio</em> (r) is -2
Henceforth, after determining what a and r are, we use the formula for the <em>nth term</em>. Which is:

Therefore, the 14th term is :

Hope it helps!
The cost of one ticket is $0.75
Option b 10.44 ...........