Answer:
Explanation:
1)
Given data:
Moles of Cl₂ react = ?
Moles of carbon = 4.55 mol
Solution:
Chemical equation:
2TiO₂ + 4Cl₂ + 3C → 2TiCl₄ + CO₂ + 2CO
Now we will compare the moles of Cl₂ with C.
C : Cl₂
3 : 4
4.55 : 4/3×4.55 = 6.1 mol
6.1 moles of chlorine will react with 4.55 moles of C.
2)
Given data:
Mass of TiO₂ react = ?
Moles of carbon = 4.55 mol
Solution:
Chemical equation:
2TiO₂ + 4Cl₂ + 3C → 2TiCl₄ + CO₂ + 2CO
Now we will compare the moles of Cl₂ with C.
C : TiO₂
3 : 2
4.55 : 2/3×4.55 = 3 mol
Mass of TiO₂:
Mass = number of moles × molar mass
Mass = 3 mol × 79.87 g/mol
Mass = 239.61 g
3)
Given data:
Molecules of TiCl₄ formed = ?
Moles of TiO₂ react = 115 g
Solution:
Chemical equation:
2TiO₂ + 4Cl₂ + 3C → 2TiCl₄ + CO₂ + 2CO
Number of moles of TiO₂:
Number of moles = mass/ molar mass
Number of moles = 115 g/ 79.87 g/mol
Number of moles = 1.44 mol
Now we will compare the moles of Cl₂ with C.
TiO₂ : TiCl₄
2 : 2
1.44 : 1.44
Molecules of TiCl₄:
1 mole = 6.022 × 10²³ molecules
1.44 ×6.022 × 10²³ molecules
8.672× 10²³ molecules
