Molar mass NaOH ( sodium hydroxide) = 40.0 g/mol
Number of moles:
n = mass / molar mass
n = 10.0 / 40.0
n = 0.25 moles
Volume = 2.0 L
Molarity = number of moles / volume in liters
M = 0.25 / 2.0
M = 0.125 M
answer D
hope this helps!
Answer:
using bond energies = - 37 kJ
using enthalpies of formation = - 45.7 kJ
Explanation:
From the reaction;
CH2═CH2(g) + H2O(g) -------> CH3CH2OH(g)
From the above reaction; there are 4 (C-H) bonds , 1 ( C=C) and 2 (H-O) of ethene which forms 5(C-H) bonds, 1 (C-C) and 1 (C-O) and 1(H-O) bonds.
Using Bond Energies; the heat of the reaction can be written as:
∑ energy of old bond breaking + ∑ energies of the new bond formation.
∑ ![[(4 * BE_{C-H}) + BE_{C-C}) + + BE_{O-H})]](https://tex.z-dn.net/?f=%5B%284%20%2A%20BE_%7BC-H%7D%29%20%20%2B%20BE_%7BC-C%7D%29%20%2B%20%20%2B%20BE_%7BO-H%7D%29%5D)
+ ∑ ![[(5 * BE_{C-H}) + BE_{C-C}) + BE_{O-H}+ BE_{C-O})]](https://tex.z-dn.net/?f=%5B%285%20%2A%20BE_%7BC-H%7D%29%20%2B%20BE_%7BC-C%7D%29%20%2B%20BE_%7BO-H%7D%2B%20BE_%7BC-O%7D%29%5D)
∑![[4*413 kJ)+(614kJ)+(2*647kJ]](https://tex.z-dn.net/?f=%5B4%2A413%20kJ%29%2B%28614kJ%29%2B%282%2A647kJ%5D)
+ ∑ ![(5*-413kJ)+(-347kJ)+(-467kJ)+(-358kJ)]](https://tex.z-dn.net/?f=%285%2A-413kJ%29%2B%28-347kJ%29%2B%28-467kJ%29%2B%28-358kJ%29%5D)
-37 kJ
To calculate the heats of reaction by using enthalpies of formation; we have:
∑ 
- ∑ 
∑ 
- ∑ 
(-235.1 kJ) - [(+52.47 kJ) + (-241.826 kJ)]
-45.7 kJ
If is an endothermic reaction.. heat is absorbed from the surrounding.. so it is Positive(+ve).. l hope it helped???
Answer:
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