Answer:
The volume of cupboard is 2.0043 m³.
Explanation:
Given data:
width of cupboard = 1.31 m
length of cupboard = 0.9 m
height of cupboard = 1.70 m
Volume = ?
Solution:
Volume = length × width × height
Volume = 0.9 m × 1.31 m × 1.70 m
Volume = 2.0043 m³
The volume of cupboard is 2.0043 m³.
Answer:
Yes, it is possible. Let us consider an example of two solutions, that is, solution A having 20 percent mass RbCl (rubidium chloride) and solution B is having 15 percent by mass NaCl or sodium chloride.
It is found that solution A is having more concentration in comparison to solution B in terms of mass percent. The formula for mass percent is,
% by mass = mass of solute/mass of solution * 100
Now the formula for molality is,
Molality = weight of solute/molecular weight of solute * 1000/ weight of solvent in grams
Now molality of solution A is,
m = 20/121 * 1000/80 (molecular weight of RbCl is 121 grams per mole)
m = 2.07
Now the molality of solution B is,
m = 15/58.5 * 1000/85
m = 3.02
Therefore, in terms of molality, the solution B is having greater concentration (3.02) in comparison to solution A (2.07).
Answer :
Incorrect
Explanation : In the given solution set of Ax = b;
is set of all vectors to form w=
p +
here
is is any solution of the equation Ax = 0;
this stands to be incorrect, as the correct would only exists when some vector
p is found to be like this
Ap=b
Answer: The amount of heat needed is = 4.3kJ
Explanation:
Amount of heat H = M × C × ΔT
M= mass of benzene = 64.7g
C= specific heat capacity = 1.74J/gK
ΔT = T2-T1
Where T1 is initai temperature = 41.9C
T2 is the final temperature( boiling point of benzene) = 80.1C
H= 64.7×1.74×80.7
H= 4300J
H=4.3kJ
Therefore, the amount of heat needed is 4.3kJ
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