Question

50g nitrous oxide combines with 50g oxygen form dinitrogen tetroxide according to the balanced equation below.

Answer 1

Limiting reactant : O₂

Mass of  N₂O₄ produced = 95.83 g

Further explanation

Given

50g nitrous oxide

50g oxygen

Reaction

2N20 + 302 - 2N204

Required

Limiting reactant

mass of N204 produced

Solution

mol N₂O :

$\tt =\dfrac{50}{44}=1.136$

mol O₂ :

$\tt =\dfrac{50}{32}=1.5625$

2N₂O+3O₂⇒ 2N₂O₄

ICE method

1.136    1.5625

1.0416  1.5625    1.0416

0.0944    0          1.0416

Limiting reactant : Oxygen-O₂

Mass N₂O₄(MW=92 g/mol) :

$\tt =mol\times MW=1.0416\times 92=95.83~g$