The point G on AB such that the ratio of AG to GB is 3:2 is; G(4.2, 2)
How to partition a Line segment?
The formula to partition a line segment in the ratio a:b is;
(x, y) = [(bx1 + ax2)/(a + b)], [(by1 + ay2)/(a + b)]
We want to find point G on AB such that the ratio of AG to GB is 3:2.
From the graph, the coordinates of the points A and B are;
A(3, 5) and B(5, 0)
Thus, coordinates of point G that divides the line AB in the ratio of 3:2 is;
G(x, y) = [(2 * 3 + 3 * 5)/(2 + 3)], [(2 * 5 + 3 * 0)/(2 + 3)]
G(x, y) = (21/5, 10/5)
G(x, y) = (4.2, 2)
Read more about Line segment partition at; brainly.com/question/17374569
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180 Degrees
Hope I helped, and good luck!
Answer:
4
Step-by-step explanation:
The given polynomial is :
p(x) = -2a⁴+8a³-9a
We need to find the degree of the polynomial.
Degree of the polynomial = degree is the value of the greatest exponent.
Here, the maximum value of the exponent is 4 in -2a⁴.
It means,
Degree of the polynomial = 4
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To solve for X, you first add the integers together and the X variables together. Then you subtract 3 from each side, followed by dividing by 3 on each side. Here is the work to show our math:
X + X + 1 + X + 2 = 154
3X + 3 = 154
3X + 3 - 3 = 154 - 3
3X = 151
3X/3 = 151/3
X = 50 1/3
Since 50 1/3 is not an integer, there is no true answer to this problem.
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