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3 years ago

1/2 x 4 + 1/2 x Z

Mathematics

2 answers:

nadezda [96]3 years ago

7 0

Answer:

D. 1/2(4 + Z)

Step-by-step explanation:

1/2 x 4 + 1/2 x Z

We can factor out a 1/2 since it is in both terms

1/2 (4+z)

kiruha [24]3 years ago

4 0

$\dfrac{1}2{\times4+\dfrac{1}{2}\times z=\boxed{\dfrac{1}{2}}\times4+\boxed{\dfrac{1}{2}}\times z=\boxed{\dfrac{1}{2}}\times(4+z)}\\\\Answer:\ \boxed{D.\ \dfrac{1}{2}(4+z)}$

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How many unique triangles can you construct with all sides having integers length, with one side of length 5 cm and a perimeter

Lisa [10]

The answer is,
Only One.

8 0

3 years ago

Continue the pattern: 3-6,12,4,20

Brrunno [24]

Answer:

The most likely solution sought is 13:

Beginning with 3: subtract 9, add 18, subtract 8, add 16, subtract 7, add 14, etc. Each time, reduce the number subtracted by one, and double that number to add.

So, beginning with 3: 3-9 = -6, -6+2(9) = 12, 12-8 = 4, 4+2(8) = 20, 20-7 = 13, etc.

*****

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A train leaves at 14:56 and arrives at 16:43. It travelled at an average speed of 135 km/h. How far did it travel? Give your ans

Firlakuza [10]

Answer:

240.8

Step-by-step explanation:

→ Calculate time taken

16:43 - 14:56 = 1 hour and 47 minutes

→ Write the speed formula and make distance the subject

Speed = Distance ÷ Time ⇔ Distance = Speed × Time

→ Convert 1 hour and 47 minutes into decimal format

1.78333333 or $1\frac{47}{60}$

→ Substitute values into formula

135 × $1\frac{47}{60}$ = 240.75

8 0

3 years ago

Find the distance, to the nearest tenth, from T(4-2) to U(-2,3)

kiruha [24]

Distance = SQRT(x^2+y^2)
x = 4 - (-2) = 6
y = 3 - 2 = 1

distance = SQRT(6^2 + 1^2) = SQRT(36+1) = SQRT(37) = 6.1

4 0

3 years ago

The number of internet users in mexico between 2004 and 2008 can be modeled as u(t) = 8.02(1.17t) million users where t is the n

maxonik [38]

Answer:

a) 1.479 Million

b) 36.9%

c) 13.668%

Step-by-step explanation:

The complete question is attached in the image below.

The number of internet users in Mexico between 2004 and 2008 is modelled by the following equation:

$u(t)=8.02(1.17)^{t}$

Where, u(t) is in millions and t is the number of years since 2004.

Part a) Rate of change of internet users between 2004 and 2006

The rate of change of a function is defined as:

$\frac{f(x_{2})-f(x_{1})}{x_{2}-x_{1}}$

We have to find the rate of change between 2004 and 2006. For 2004 t = 0, and for 2006, t = 2. So the rate of change for the given function will be:

$\frac{u(2)-u(0)}{2-0}\\\\ =\frac{8.02(1.17)^{2}-8.02(1.17)^{0}}{2}\\\\ =1.479$

Thus, the average rate of change in number of internet users in Mexico from between 2004 and 2006 was 1.479 million.

Part b) Percentage change of internet users between 2004 and 2006

The formula to calculate the percentage change is:

$\frac{\text{New value - Original Value}}{\text{Original Value}} \times 100\%$

Here, New value means the users in 2006 and original value means the users in 2004.

Using the values in this formula, we get:

$\frac{8.02(1.17)^{2}-8.02(1.17)^0}{8.02(1.17)^{0}} \times 100\%\\\\ =36.89\%$

Thus, the percentage change in the number of internet users between 2004 and 2006 was 36.89%

Part c) Percentage of internet users in 2008

For 2008, t would be equal to 4.

So, the number of internet users in Mexico in 2008 would be = $8.02(1.17)^{4}=15.02857542$ million = 15,028,575 (rounded to nearest integer)

Total population of Mexico in 2008 = 109,955,400

We have to calculate what percentage of Mexico population was Internet users in 2008. The formula for this would be:

$\frac{\text{Concerned Value}}{\text{Total Value}} \times 100\%$

Here, concerned value is the number of internet users and total value is the total population. Using the values in this formula we get:

$\frac{15028575}{109955400} \times 100\%\\\\=13.668\%$

Thus, 13.668% of the population was internet users in 2008 in Mexico.

5 0

3 years ago