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Mashutka [201]
3 years ago
9

If ab ≠ 0, which is equivalent to

Mathematics
2 answers:
Mazyrski [523]3 years ago
5 0

Since ab don't have any values yet, you must break it down now knowing ab doesn't equal 0.

Answer: -2a^2

marissa [1.9K]3 years ago
4 0

Answer:

-12a³b²/(6ab²)=-2a^(3-1)=-2a²

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The sum of two numbers exceeds their product by one.Their difference is equal to their products less five .Find the two numbers
Ludmilka [50]

Answer:

1 and 3

Step-by-step explanation:

If the two numbers are x and y, then:

x + y = xy + 1

x − y = xy − 5

Subtract the two equations:

(x + y) − (x − y) = (xy + 1) − (xy − 5)

x + y − x + y = xy + 1 − xy + 5

2y = 6

y = 3

Solve for x:

x + 3 = 3x + 1

2 = 2x

x = 1

The numbers are 1 and 3.

4 0
3 years ago
What is 5/6 plus 7/8?
irina [24]

Answer:

1  17/24

Step-by-step explanation:

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Which set of side lengths could be used to make a triangle?
GarryVolchara [31]

Answer: 22, 8, 27

Step-by-step explanation: the sum of the 2 shorter sides must be greater than longest side

6 0
3 years ago
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What is 25 and 5/8-12
Burka [1]
92/3, i calculated 25+5/8 over 12
and if u divide 92/3 u get 30.66
6 0
3 years ago
Two pedestrians simultaneously left two villages 27 km apart and walked toward each other. the first one walked 4 km per hour, a
Salsk061 [2.6K]

<u>Step 1: Assign variable for the unknown that you need to find. </u>

Let ' t ' be the number of hours it took for the pedestrians to meet.

<u>Step 2: List the give details</u>

Speed of first pedestrian = 4 km/hr.

Speed of second pedestrian = 6 km/hr.

Distance between two pedestrians = 27 km.

<u>Step 3: Set up an equation</u>

The relationship between speed, distance and time is given below:

Distance= \; Rate \times Time

The first one walked 4 km per hour, distance traveled by first pedestrian is given below:

Distance_{1^{st} \; pedestrian} \; = \; 4t\\\\Distance_{2^{nd} \; pedestrian} \; = \; 6t

Two pedestrians simultaneously left two villages 27 km apart and walked toward each other.

Distance_{1^{st} \; pedestrian} +Distance_{2^{nd} \; pedestrian} =27\\\\4t+6t=27\\Combine \; Like \; Terms\\\\10t=27\\Dividing \; 10 \; on \; both \; sides\\\\ \frac{10t}{10}  = \frac{27}{10}  \\Simplifying \; fraction \; on \; both \; sides\\\\t=2.7 \; hours

Conclusion:

The pedestrian meet after 2.7 hours.

3 0
3 years ago
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