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tia_tia [17]
3 years ago
7

AWNSER FIST GET BRANLISET :-)and please help PLEASE

Mathematics
2 answers:
fiasKO [112]3 years ago
8 0
The answer would be D
Vlad1618 [11]3 years ago
4 0
B. This is because length is represented by X in a coordinate grid. X is always the first point in a coordinate set. 4 + 1 is you equation to determine the length.
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Calculate the area of figure below​
tigry1 [53]

Answer:

42

Step-by-step explanation:

6*8=48

3*2=6

48-6=42

3 0
3 years ago
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Which statement about the graph of the function f(x)=2x^2-x-6 are true?
Snezhnost [94]
C the vertex of the function
7 0
3 years ago
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A random sample of 4"4 fields" of barley has a mean yield of "49.6"49.6 bushels per acre and standard deviation of 7.997.99 bush
ExtremeBDS [4]

Answer:

The critical value that should be used in constructing the interval is T = 5.8408.

The 99% confidence interval for the true mean yield is between 2.943 bushels per acre and 96.268 bushels per acre.

Step-by-step explanation:

We have the standard deviation of the sample, so we use the students t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 4 - 1 = 3

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 3 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.995. So we have T = 5.8408. This is the critical value.

The margin of error is:

M = T*s = 5.8408*7.99 = 46.668 bushels per acre

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 49.6 - 46.668 = 2.943 bushels per acre.

The upper end of the interval is the sample mean added to M. So it is 49.6 + 46.668 = 96.268 bushels per acre.

The 99% confidence interval for the true mean yield is between 2.943 bushels per acre and 96.268 bushels per acre.

8 0
4 years ago
Help plsss I’m a little confused<br> We started this today :/
belka [17]
We can’t see the question
3 0
3 years ago
Read 2 more answers
Hello! Please Help Its just one simple Question ^^
Flura [38]

\\ \sf\longmapsto f(x)=112-kx

  • f(-3)=121

Put -3 in f(x)

\\ \sf\longmapsto f(-3)=121

\\ \sf\longmapsto 112-k(-3)=121

\\ \sf\longmapsto 112+3k=121

\\ \sf\longmapsto 3k=9

\\ \sf\longmapsto k=3

4 0
3 years ago
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