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tia_tia [17]
2 years ago
7

AWNSER FIST GET BRANLISET :-)and please help PLEASE

Mathematics
2 answers:
fiasKO [112]2 years ago
8 0
The answer would be D
Vlad1618 [11]2 years ago
4 0
B. This is because length is represented by X in a coordinate grid. X is always the first point in a coordinate set. 4 + 1 is you equation to determine the length.
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Answer: 60

Step-by-step explanation:

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natka813 [3]

Answer:

x= -8 , y = 5

x= 25/4 , y = 1/4

Step-by-step explanation:

substitute first eqn into the second eqn:

(7 - 3y)^2 -y^2 = 39

49 - 42y + 9y^2 - y^2 = 39

8y^2 - 42y +10 =0

4y^2 - 21y + 5 = 0

(4y-1) (y-5) = 0

y= 1/4 , 5

when y=1/4

x = 7- 3/4

=25/4

when y= 5

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3 years ago
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"Find the sum of the first 50 term in this sequence 4, 7, 10, 13, ...". How do i do this without writing them all out, and how d
melisa1 [442]
First term ,a=4 , common difference =4-7=-3, n =50
sum of first 50terms= (50/2)[2×4+(50-1)(-3)]
=25×[8+49]×-3
=25×57×-3
=25× -171
= -42925
derivation of the formula for the sum of n terms
Progression, S
S=a1+a2+a3+a4+...+an

S=a1+(a1+d)+(a1+2d)+(a1+3d)+...+[a1+(n−1)d]   →   Equation (1)

S=an+an−1+an−2+an−3+...+a1

S=an+(an−d)+(an−2d)+(an−3d)+...+[an−(n−1)d]   →   Equation (2)

Add Equations (1) and (2)
2S=(a1+an)+(a1+an)+(a1+an)+(a1+an)+...+(a1+an)

2S=n(a1+an)
S=n/2(a1+an)

Substitute an = a1 + (n - 1)d to the above equation, we have
S=n/2{a1+[a1+(n−1)d]}
S=n/2[2a1+(n−1)d]
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Alex787 [66]

Answer:

56

Step-by-step explanation:

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3 years ago
Which statement is always true about two congruent polygons?
Oduvanchick [21]

Answer:The number of angles & sides is always the same.

Step-by-step explanation:

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2 years ago
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