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yaroslaw [1]
3 years ago
5

I need help with this ​

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
8 0

Answer:

I looked it up and it said #3 is an integer #4 is a negitive integer

Step-by-step explanation:

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How to write 168.7 in expanded form
nadya68 [22]

Answer:

100 + 60 + 8 + 0.7

Step-by-step explanation:

Expanded form or expanded notation is a way of writing numbers to see the value of individual digits.

3 0
3 years ago
Read 2 more answers
Geometry help please. Thank you. I picked C but that answer is wrong. What term Describes RT?
Fiesta28 [93]

Answer:

angle bisector

Step-by-step explanation:

RT is an angle bisector of the triangle

6 0
2 years ago
(2*1) +(6*1/1,000) write in standard form
Pani-rosa [81]
Multiply and add it up and you got ur answer
7 0
3 years ago
CUALES SON LOS GRADOS PARA HACER UNA GRAFICA DE PASTEL, CON LOS SIGUIENTES PORCENTAJES( 20%,50%,10%)
svlad2 [7]

Answer:

Lo primero que debemos saber, es que la gráfica de pastel nos permite dividir a una población, la cual sería el 100%, en porcentajes menores que representan algo.

En este caso tenemos los porcentajes 20%, 50%, 10%  (notar que no suman 100%, entonces nos falta algún porcentaje)

Bueno, como sabemos el gráfico (el cual es un círculo) representa el 100%.

Y en un círculo, tenemos un ángulo de 360°

Entonces comenzamos con la equivalencia:

360° = 100%

Entonces, ¿a que grado corresponde el 50%? Planteamos la ecuación:

x = 50%

Si tomamos el cociente entre las ecuaciones:

x = 50% y  360° = 100%

obtenemos:

x/360° = 50%/100%

resolviendo para x, obtenemos:

x = (50%/100%)*360° = 0.5*360° = 180°

Para los otros porcentajes hacemos lo mismo.

Para el de 20% tenemos:

y = 20%

planteamos la ecuación:

y/360° = 20%/100%

y = 0.2*360° = 72°

Finalmente, para el de 10% tendremos:

z = 10%

planteando la ecuación como antes:

z/360° = 10%/100%

z = 0.1*360 = 36°

Asi, hemos encontrado los grados correspondientes para cada porcentaje.

8 0
3 years ago
Answering these questions
Rudiy27
1.\\ a)\ y=2x-3\ \ \ |subtract\ y\ from\ both\ sides\\\\\boxed{2x-y-3=0}\\\\b)\ y=\dfrac{1}{3}x-\dfrac{2}{5}\ \ \ |multiply\ both\ sides\ by\ 15\\\\15y=5x-3\cdot2\ \ \ |subtract\ 15y\ from\ both\ sides\\\\\boxed{5x-15y-6=0}


2.\\a)\ 5x-y+3=0\ \ \ |add\ y\ to\ both\ sides\\\\\boxed{y=5x+3}\\\\d)\ 7x+2y-3=0\ \ \ |subtract\ 7x\ from\ both\ sides\\\\2y-3=-7x\ \ \ |add\ 3\ to\ both\ sides\\\\2y=-7x+3\ \ \ \ |divide\ both\ sides\ by\ 2\\\\\boxed{y=-3.5x+1.5}


3.\\y=25x+100\ \ \ \ |subtract\ y\ from\ both\ sides\\\\\boxed{25x-y+100=0}
6 0
3 years ago
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