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3 years ago

In which quadrant does the point (–10, 9) lie?

Mathematics

2 answers:

Furkat [3]3 years ago

5 0

A. Quadrant I is the correct answer.

x axis is -10 and y axis is 9

Luden [163]3 years ago

3 0

Quadrant I because since the first one is -10, the negative side is on the left, in quandrant I

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True or false: 4/8 and 10/16 are equivalent fractions?

lorasvet [3.4K]

Answer:

False

Step-by-step explanation:

Multiply 8 by 2 to create the common denominator (which is 16).

Now multiply 4 by 2 to keep the fraction even.

This gives you the fraction 8/16 which is not equivalent to 10/16.

Another way you could write this inequality:

8/16 < 10/16

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3 years ago

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12,,389+15

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3 years ago

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Answer:

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3 years ago

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What is the solution of the equation over the complex numbers

denis-greek [22]

Answer:

$2i\sqrt{3}$

$-2i\sqrt{3}$

Step-by-step explanation:

$x^2 + 12$

First set the equation to 0

$x^2 + 12$

$x^2 + 12 = 0$

Second, get the 12 on the right side of the equal sign by adding a -12 to each side

$x^2 + 12 = 0$

$x^2 + 12 + (-12) = 0 -12$

$x^2 = -12$

Square root both sides of the equal sign.

$x^2 = -12$

$\sqrt{x^2} = \sqrt{-12}$

Take the square root on left sides of the equal sign.

$\sqrt{x^2} = \sqrt{-12}$

$x = \sqrt{-12}$

Take the square root on the right side of the equal sign. Remember $\sqrt{-1} = i$

$x = \sqrt{-12}$

$x = \sqrt{4}*\sqrt{-1}\sqrt{3}}$

$x = 2i\sqrt{3}$

AND

$x = -2i\sqrt{3}$

8 0

3 years ago

VERBAL

telo118 [61]

Answer:

The initial value in the word problem is the output value when input value is set to zero.

Step-by-step explanation:

In the question, it is given that a problem uses a linear function.

It is required to explain how to interpret the initial value in a word problem.

In order to find the initial value in a world problem, find the output value when input value is set to zero.

If the initial value is marked as b for a linear function f(x), find it as follow,

b = f (x=0)

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1 year ago