Answer:
![-\frac{54}{7}](https://tex.z-dn.net/?f=-%5Cfrac%7B54%7D%7B7%7D)
Step-by-step explanation:
The first number is ![\sqrt{\frac{64}{4} }](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B64%7D%7B4%7D%20%7D)
We simplify to get:![\sqrt{\frac{64}{4} }=\sqrt{16}=4](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B64%7D%7B4%7D%20%7D%3D%5Csqrt%7B16%7D%3D4)
The second number is
.
This number can be rewritten as ![7 \frac{5}{7}=7.714285714287](https://tex.z-dn.net/?f=7%20%5Cfrac%7B5%7D%7B7%7D%3D7.714285714287)
This is not an integer
The third number is ![(\frac{-25}{5})^2](https://tex.z-dn.net/?f=%28%5Cfrac%7B-25%7D%7B5%7D%29%5E2)
We simplify to get: ![(\frac{-25}{5})^2=(-5)^2=25](https://tex.z-dn.net/?f=%28%5Cfrac%7B-25%7D%7B5%7D%29%5E2%3D%28-5%29%5E2%3D25)
This is also an integer.
The correct answer is
.
Solution :
The normal body temperature of any human body is considered to be 98.6
. But there is a constant debate about the body temperature of a long held standard to the body temperature.
It is given that :
Null hypothesis and alternate hypothesis :
![$H_0 : \mu = 98.6$](https://tex.z-dn.net/?f=%24H_0%20%3A%20%5Cmu%20%3D%2098.6%24)
And ![$H_A : \mu > 98.6$](https://tex.z-dn.net/?f=%24H_A%20%3A%20%5Cmu%20%3E%2098.6%24)
n is given as = 180
Test statistics = 3.64
Prove = 0.018 < α = 0.05 (let reject null hypothesis for α = 0.05 )
Therefore, their results are statistically significant and the result is unlikely due to chance alone.
Answer:
8 days
Step-by-step explanation:
If the frog crawls up 4 feet and slips back 2 feet, then it will crawl...
4-2 = 2 ft each day
Let x be the amount of days it'll take for the frog to reach the top of the well given he crawls 2 feet each day:
2x=18
Divide both sides by 2
x=9
But, at 7 days, the frog will already have crawled 14 feet. This means that on the 8th day, the frog will crawl 4 feet and reach the top of the well before he slips back down. Therefore the answer is 8 days
Answer:
<em>a. Graph A and Graph C</em>
Step-by-step explanation:
Those were the only graphs that pass the vertical line test.