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3 years ago

7

a rectangle had a width of 5m+12. Its length was twice the width. what was the length of the rectangle? and what was the perimet

er or the rectangle?

1 answer:

Digiron [165]3 years ago

4 0

The lengh= 2*(5m+12)=2*5m+2*12=10m+24

the lengh+the width=10m+24+5m+12=15m+36

P=2(the lengh+the width)
P =2*(15m+36)=2*15m+2*36=30m+72

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