Answer:
Proportion of all bearings falls in the acceptable range = 0.9973 or 99.73% .
Step-by-step explanation:
We are given that the diameters have a normal distribution with a mean of 1.3 centimeters (cm) and a standard deviation of 0.01 cm i.e.;
Mean, = 1.3 cm and Standard deviation, = 0.01 cm
Also, since distribution is normal;
Z = ~ N(0,1)
Let X = range of diameters
So, P(1.27 < X < 1.33) = P(X < 1.33) - P(X <=1.27)
P(X < 1.33) = P( < ) = P(Z < 3) = 0.99865
P(X <= 1.27) = P( < ) = P(Z < -3) = 1 - P(Z < 3) = 1 - 0.99865
= 0.00135
P(1.27 < X < 1.33) = 0.99865 - 0.00135 = 0.9973 .
Therefore, proportion of all bearings that falls in this acceptable range is 99.73% .
Answer:
3
Step-by-step explanation:
down 3 over 1 3/1 or 3.
Hope this helps plz hit the crown ;D
Answer:
24
Step-by-step explanation:
Just subtract the first quartile form the third quartile.
third quartile - first quartile
32 - 8 = 24 IQR
FIRST quartile: 8
SECOND quartile: 20
THIRD quartile: 32
So the IQR is 24
Hope this helps :)
Answer:
this will b the anwser
Step-by-step explanation: