A gas can holds 10 liters of gas. How many cans could we fill with 35 liters of gas?

Mathematics

1 answer:

iris [78.8K]3 years ago

5 0

Answer:

3 and 1/2

Step-by-step explanation:

because if one can holds 10 liters of gas, three cans would hold 30 because 10 times 3 is 30 plus the extra 5 liters in the remaining can

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Mrs travis wants to have the clown deliver balloons to her secretary's office. Clowns R Fun charges $1.25 per balloon and $6 for

marysya [2.9K]

The <em>correct answer</em> is:

6 balloons.

Explanation:

Let x represent the number of balloons purchased.

We will call the function for Clowns R Fun c(x):

c(x) = 1.25x+6

We will call the function for Singing Balloons s(x):

s(x) = 1.95x+2

We want the amount for Clowns R Fun, c(x) to be less:

c(x) < s(x)

1.25x+6 < 1.95x+2

Subtract 1.25x from each side:

1.25x+6-1.25x < 1.95x+2-1.25x

6 < 0.7x+2

Subtract 2 from each side:

6-2 < 0.7x+2-2

4 < 0.7x

Divide each side by 0.7:

4/0.7 < 0.7x/0.7

5.7 < x

x > 5.7

She must buy more than 5.7 balloons; the next integer up is 6. She must buy 6 or more balloons.

7 0

3 years ago

Read 2 more answers

Solve each system of linear equations albebraically

ANEK [815]

Step-by-step explanation:

$1.\\\left\{\begin{array}{ccc}y=3x&(1)\\2y=6x&(2)\end{array}\right\\\\\text{Substitute (1) to (2):}\\\\2(3x)=6x\\6x=6x\qquad\text{subtract}\ 6x\ \text{from both sides}\\6x-6x=6x-6x\\0=0\qquad\text{TRUE}\\\\Answer:\ \text{Infinitely many solutions}\\\\\left\{\begin{array}{ccc}y=3x\\x\in\mathbb{R}\end{array}\right$

$2.\\\left\{\begin{array}{ccc}y=2x+5&(1)\\y-2x=1&(2)\end{array}\right\\\\\text{Substitute (1) to (2):}\\\\(2x+5)-2x=1\\2x+5-2x=1\qquad\text{combine like terms}\\(2x-2x)+5=1\\5=-1\qquad\text{FALSE}\\\\Answer:\ \text{No solution.}$

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