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mylen [45]
3 years ago
10

1 pint= 1/8 gallon. How many pints are there in 2/3 gallon.

Mathematics
2 answers:
FrozenT [24]3 years ago
5 0

gallon = pint *0.125

gallon = pint / 8
0.125+0.125+0.125+0.125+0.125+0.125+0.125+0.125+0.125+0.125+0.125+

0.125+0.125+0.125+0.125+0.125 = 2

16 would be the answer I believe, maybe I'm wrong, double check.

zzz [600]3 years ago
5 0

Answer:

5 1/3 pints

Step-by-step explanation:

1 pint is 1/8gal and u need to find how many pints in 2/3 gal so it'll be 2/3 ÷ 1/8 which is 5 1/3

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What x and y equal to
Papessa [141]

Answer:

X = 4, Y = 3.

Explanation:

Since the length of side CK is equal to the length of WM, then you can make the equation 6y-4 = 18. then you just add 4 to each side and divide both sides by six to get 3. Same thing for the other equation. Angle (i think its an angle due to its placement) C is equal to angle M, so you can make the equation 3x + 7 = 19. Subtract seven from both sides then divide by 3 to get 4. Tell me if you have any questions :)

6 0
3 years ago
Read 2 more answers
A scientist begins with 250 grams of a radioactive substance. After 250 minutes, the sample has decayed to 32 grams. Rounding to
s2008m [1.1K]

Answer:

Part 1 : A=250 e^{-0.008223t}

Part 2 : Half life is 84 minutes ( approx )

Step-by-step explanation:

Part 1 : Suppose the function that shows the amount( in grams ) of the substance after t minutes,

A=A_0 e^{kt}

If t = 0 min, A = 250 grams,

250=A_0 e^{0}

\implies A_0 = 250

If t = 250, A = 32 grams,

32 = A_0 e^{250k}

32 = 250 e^{250k}

0.128 = e^{250k}

Taking ln both sides,

\ln(0.128) = 250k

\implies k =\frac{\ln(0.128)}{250}=-0.008223

Hence, the equation that shows this situation,

A=250 e^{-0.008223t}

Part 2 : If A = 250/2 = 125,

125 = 250 e^{-0.008223t}

0.5 = e^{-0.008223t}

Taking ln both sides,

\ln(0.5) = -0.008223t

\implies t =\frac{\ln(0.5)}{-0.008223}\approx 84

Therefore, the half life of the substance would be 84 minutes.

8 0
3 years ago
The average score of all golfers for a particular course has a mean of 61 and a standard deviation of 3.5 . Suppose 49 golfers p
Nadya [2.5K]

Answer:

The probability that the average score of the 49 golfers exceeded 62 is 0.3897

Step-by-step explanation:

The average score of all golfers for a particular course has a mean of 61 and a standard deviation of 3.5

\mu = 61

\sigma = 3.5

We are supposed to find he probability that the average score of the 49 golfers exceeded 62.

Formula : Z=\frac{x-\mu}{\sigma}

Z=\frac{62-61}{3.5}

Z=0.285

Refer the z table for p value

p value = 0.6103

P(x>62)=1-P(x<62)=1-0.6103=0.3897

Hence the probability that the average score of the 49 golfers exceeded 62 is 0.3897

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4 years ago
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Answer:

The domain is all the x-values, and the range is all the y-values

Step-by-step explanation:

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