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4 years ago

Subtract the quotient of 5 ÷ 3 from the sum of 33 and 7

Mathematics

1 answer:

USPshnik [31]4 years ago

5 0

( 33 + 7) - (5/3)
= 40 - 5/3
= 38 6/3 - 5/3
= 38 1/3

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Garrett buys a bag of cookies that contains 8 chocolate chip cookies, 6 peanut butter cookies, 7 sugar cookies and 7 oatmeal coo

Lina20 [59]

Answer:

p(chocolate chip) = 2/7

p(oatmeal) = 7/27

Step-by-step explanation:

probability = favorable outcomes/total outcomes

First, add up all the cookies in the bag.

8 + 6 + 7 + 7 = 28

Next find the probability of selecting a chocolate chip cookie. Since there are 8 chocolate chip cookies and 28 cookies in the bag, create a fraction.

p(chocolate chip) = 8/28

reduce by 4

p(chocolate chip) = 2/7

Now that the cookie was eaten that will reduce the number of chocolate chip cookies to 7 and the overall number of cookies to 27.

There are 7 oatmeal cookies and 27 total cookies, so create the fraction.

p(oatmeal) = 7/27

5 0

3 years ago

For a snack, mrs graham gives her student graham crackers. She has a package of 20 graham crackers to share equally to 8 student

lara31 [8.8K]

Answer:

2.5

Step-by-step explanation:

graham crackers each student receive = total number of crackers / total number of students

20 / 8 = 2.5

3 0

3 years ago

Tony has $18 to buy apples and bananas for a fruit salad. Apples cost $2 per pound and bananas cost $1 per pound. Write and grap

tester [92]

Answer:

21;-;?

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4 0

3 years ago

Find (f ∘ g)(-6) when f(x) = 9x + 2 and g(x) = -9x2 - 2x + 1.

Salsk061 [2.6K]

Given that the two functions are $f(x)=9x+2$ and $g(x)=-9x^2-2x+1$

We need to determine the value of $(f \circ g)(-6)$

The value of $(f \circ g)(x)$ :

The value of $(f \circ g)(x)$ can be determined using the formula,

$(f \circ g)(x)=f[g(x)]$

Substituting $g(x)=-9x^2-2x+1$ in the above formula, we get;

$(f \circ g)(x)=f[-9x^2-2x+1]$

Now, substituting $x=-9 x^{2}-2 x+1$ in the function $f(x)=9x+2$ , we get;

$(f \circ g)(x)=9(-9x^2-2x+1)+2$

$(f \circ g)(x)=-81x^2-18x+9+2$

$(f \circ g)(x)=-81x^2-18x+11$

Thus, the value of $(f \circ g)(x)$ is $(f \circ g)(x)=-81x^2-18x+11$

The value of $(f \circ g)(-6)$ :

The value of $(f \circ g)(-6)$ can be determined by substituting x = -6 in the function $(f \circ g)(x)=-81x^2-18x+11$

Thus, we have;

$(f \circ g)(-6)=-81(-6)^2-18(-6)+11$

$(f \circ g)(-6)=-81(36)-18(-6)+11$

$(f \circ g)(-6)=-2916+108+11$

$(f \circ g)(-6)=-2797$

Thus, the value of $(f \circ g)(-6)$ is -2797

Hence, Option B is the correct answer.

8 0

4 years ago

Which of the following is not equal to cos⁡(520°)?

Gnoma [55]

The cosine repeats itself every 360 degrees, and it mirrors at 0 and 180 degrees. It inverts around 90 and 270.
So without using a calculator, you can tell that:

cos(520)=cos(520-360)=cos(160)
cos(160) = cos(180-20) = cos(180+20) = cos(200)
cos(160) is NOT equal to cos(20), it would be -cos(20).
cos(160) = -cos(20) = -cos(-20)

So C is the only one unequal.

8 0

3 years ago

Read 2 more answers