An airplane is flying at 350 km/h in a direction of 349 degrees. Find the westerly and northerly components of its velocity.

Describe how to transform the graph of g(x)= ln x into the graph of f(x)= ln (3-x) -2.

Strike441 [17]

Answer:

The graph of g(x) = ㏑x translated 3 units to the right and then reflected

about the y-axis and then translated 2 units down to form the graph of

f(x) = ㏑(3 - x) - 2

Step-by-step explanation:

* Lets talk about the transformation

- If the function f(x) reflected across the x-axis, then the new

function g(x) = - f(x)

- If the function f(x) reflected across the y-axis, then the new

function g(x) = f(-x)

- If the function f(x) translated horizontally to the right

by h units, then the new function g(x) = f(x - h)

- If the function f(x) translated horizontally to the left

by h units, then the new function g(x) = f(x + h)

- If the function f(x) translated vertically up

by k units, then the new function g(x) = f(x) + k

- If the function f(x) translated vertically down

by k units, then the new function g(x) = f(x) – k

* lets solve the problem

∵ Graph of g(x) = ㏑x is transformed into graph of f(x) = ㏑(3 - x) - 2

- ㏑x becomes ㏑(3 - x)

∵ ㏑(3 - x) = ㏑(-x + 3)

- Take (-) as a common factor

∴ ㏑(-x + 3) = ㏑[-(x - 3)]

∵ x changed to x - 3

∴ The function g(x) translated 3 units to the right

∵ There is (-) out the bracket (x - 3) that means we change the sign

of x then we will reflect the function about the y-axis

∴ g(x) translated 3 units to the right and then reflected about the

y-axis

∵ g(x) changed to f(x) = ㏑(3 - x) - 2

∵ We subtract 2 from g(x) after horizontal translation and reflection

about y-axis

∴ We translate g(x) 2 units down

∴ g(x) translated 3 units to the right and then reflected about the

y-axis and then translated 2 units down

* The graph of g(x) = ㏑x translated 3 units to the right and then

reflected about the y-axis and then translated 2 units down to

form the graph of f(x) = ㏑(3 - x) - 2

7 0

3 years ago

Read 2 more answers

What’s the median of 28,45,12,34,36,45,19,20

Ipatiy [6.2K]

Answer:

Median = 31

Step-by-step explanation:

The median is the middle number which comes after arranging the set in ascending order.

Here, the given data is: 28, 45, 12, 34, 36, 45, 19, 20

The data arranged in the ascending order is as follows:

12, 19, 20, 28, 34, 36, 45, 45

Since the number of terms is even, we have two middle numbers, viz.,

28 and 34

The median would be the average of these two.

Therefore, Median = 28+34/2

= 31

The answer is 31.

5 0

4 years ago

Please answer asap! Will mark brainliest

Ierofanga [76]

1. (-3.5, -2)
2. (3.5, 2)
3. (3.5, -2)
4. (-3.5, 2)
4 is the answer

5 0

4 years ago

Read 2 more answers

A circle is centered on point B. Points A. C and D lie on its circumference.

olga_2 [115]

Answer:

So, ADC = 124/2 => ⛰ ADC = 62°

Step-by-step explanation:

If ABC i.e angle of centra = 124°

If ABC i.e angle of centra = 124°Then, we know that angle at any where of Circle is 1/2 if central angle 

If ABC i.e angle of centra = 124°Then, we know that angle at any where of Circle is 1/2 if central angle So, ADC = 124/2 => ⛰ ADC = 62°.

Thank You ☺️ ☺️. 

<h3>☆ ★ Make It Brainlist Answer Please.... </h3>

5 0

4 years ago

Read 2 more answers

A manufacturing process has a? 70% yield, meaning that? 70% of the products are acceptable and? 30% are defective. if threethree

Setler79 [48]

1. Assume the manufacturer produced 100 products.

2. 70 are acceptable and 30 are defective.

3. the first product has a probability of 70/100 to be selected from the acceptable ones. The second 69/99 (one is removed from the good ones) and the third one 68/98

4. so P(pick 3 consecutive acceptable products)= $\frac{70}{100}* \frac{69}{99}* \frac{68}{98}= \frac{7*69*68}{10*99*98}=$ =0.339

5. If familiar to the Combination formula C(n, r)= $\frac{n!}{r!(n-r)!}$ :

P(picking 3 acceptable out of 100)=n(picking 3 acceptable)/n(picking 3)=C(70, 3)/C(100/3)= $\frac{70!}{3!67!}/\frac{100!}{3!97!}=\frac{70*69*68*67!}{3!67!}/\frac{100*99*98*97!}{3!97!}= \frac{70*69*68}{3!}/\frac{100*99*98}{3!}= \frac{70*69*68}{100*99*98}$ = 0.339

7 0

4 years ago

An airplane is flying at 350 ​km/h in a direction of 349 degrees. Find the westerly and northerly components of its velocity.

An airplane is flying at 350 km/h in a direction of 349 degrees. Find the westerly and northerly components of its velocity.