Answers:
- Part A) There is one pair of parallel sides
- Part B) (-3, -5/2) and (-1/2, 5/2)
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Explanation:
Part A
By definition, a trapezoid has exactly one pair of parallel sides. The other opposite sides aren't parallel. In this case, we'd need to prove that PQ is parallel to RS by seeing if the slopes are the same or not. Parallel lines have equal slopes.
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Part B
The midsegment has both endpoints as the midpoints of the non-parallel sides.
The midpoint of segment PS is found by adding the corresponding coordinates and dividing by 2.
x coord = (x1+x2)/2 = (-4+(-2))/2 = -6/2 = -3
y coord = (y1+y2)/2 = (-1+(-4))/2 = -5/2
The midpoint of segment PS is (-3, -5/2)
Repeat those steps to find the midpoint of QR
x coord = (x1+x2)/2 = (-2+1)/2 = -1/2
y coord = (x1+x2)/2 = (3+2)/2 = 5/2
The midpoint of QR is (-1/2, 5/2)
Join these midpoints up to form the midsegment. The midsegment is parallel to PQ and RS.
Answer:
Any linear equation of the slope-intercept form y =7x/4+ b will be parallel to y=7x/4, since the slope of 7/4 will be the same for all such lines
Step-by-step explanation:
Answer:
19
Step-by-step explanation:
maximum no. of bag filled by 4275 sweets,is
4275/28 ~=152
therefore , there is 4256 sweets in 152 bags
therefore,4275-4256=19 sweets are left
Answer:
h(x) = 2x²+2
Step-by-step explanation:
Given the function g is defined as follows.
g(x) = 2x²+7
If the graph is translated by 5units vertically downwards, this means that the function will be reduced by 5 units to have;
h(x) = 2x²+7 - 5
h(x) = 2x²+2
Given:
Planes X and Y are perpendicular to each other
Points A, E, F, and G are points only in plane X
Points R and S are points in both planes X and Y
Lines EA and FG are parallel
The lines which could be perpendicular to RS are EA and FG.
