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kakasveta [241]
2 years ago
15

12 cm

Mathematics
1 answer:
Ahat [919]2 years ago
4 0

Answer:

The answer is 200 cm³

Step-by-step explanation:

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What is the output value for the following function, f(x) = 5x - 2 if the input value is 3?
Zanzabum
F(x)=5x-2
y=5x-2
y=5(3)-2
y=15-2
y=13

so the answer is B. 13
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2 years ago
What is the solution of this linear system? x+y=13
igor_vitrenko [27]

Answer:

The solution of the linear equation is: (6,7)

Step-by-step explanation:

This being that:

x + y = 13

1/2x + y = 10

What you do in order to find the solution is either (2 ways):

- Substitution

- Elimination

I'm sure that either way, you'll get the same thing. I used: Substitution.

To do this choose either if you want to find [x] or [y] first, then substitute it in. I will choose to find [x] first.

<h2>x + y = 13</h2><h2><u>           - y </u>    </h2><h2>x = 13 - y</h2>

Now substitute it into:  

1/2x + y = 10

1/2(13 - y) + y = 10

1/2(13 -y) + y= 10

<h2>Then to get rid of fraction, instead of dividing, you multiply with reciprocal</h2><h2>1/2 · 2/1 (They cancel out) Leaving you with:</h2><h3 /><h3>(13 - y) 2(y) = 2(10)</h3><h3>(Everything is multiplied, except for 13 - y, because it had parenthesis to protect it.)</h3><h3>13 - y + 2y = 20</h3><h3 /><h2>13 + y = 20</h2><h2><u>- 13       - 13</u></h2><h2>           <u>y = 7</u></h2><h2 /><h2>You now have your [y] for your coordinate.</h2><h2>(x, 7), now time to find your [x]</h2><h2 />

Now you substitute your [y] into your equation:

1/2x + (7) = 10

<h2>1/2x + 7 = 10</h2><h2><u>          -7 = -7</u></h2><h2>1/2x = 3</h2><h2>(To get rid of fraction, multiply on both sides with reciprocal)</h2><h2>1/2 cancels out with 2/1</h2><h2>x = 2(3)</h2><h2>x = 6</h2><h2>You now have your [x] coordinate.</h2><h2 /><h2>This is your coordinate: </h2><h2>(6,7)</h2><h2></h2>

 

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3 years ago
Train A and train B leave a central station at the same time. They travel the same speed, but in opposite directions, with train
ratelena [41]
Recall your d  = rt, distance = rate * time

so, keeping in mind that both trains are going at the same speed, say speed of "r" mph, after 212 hours A arrived at station A and after 4 hours, B arrived at station B.

now, the distance covered by train A is say "d", we know both stations are 585 miles apart, so, if train A covered "d" miles in those 212 hours, then train B covered the slack from 585 and d, that is "585 - d".

\bf \begin{array}{lccclll}&#10;&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\&#10;&------&------&------\\&#10;\textit{Train A}&d&r&212\\&#10;\textit{Train B}&585 - d&r&4&#10;\end{array}&#10;\\\\\\&#10;\begin{cases}&#10;\boxed{d}=212r\\&#10;585-d=4r\\&#10;----------\\&#10;585-\boxed{212r}=4r&#10;\end{cases}&#10;\\\\\\&#10;585=216r\implies \cfrac{585}{216}=r\implies \cfrac{65}{24}=r\implies \stackrel{mph}{2\frac{17}{24}}=r
8 0
2 years ago
Read 2 more answers
MS. Kitts works at a music store. Last week she sold 6 more than 3 times the number of CDs that she sold this week. Ms. Kitts so
puteri [66]

x - 3y = 6 and x + y = 110 represents the system of equations used to find x, the number of CDs she sold last week, and y, the number of CDs she sold this week

number of CDs Kitts sold last week "x" is 84 and number of CDs she sold this week "y" is 26

<h3><u>Solution:</u></h3>

Let "x" be the number of CDs Kitts sold last week

Let "y" be the number of CDs she sold this week

<em><u>Given that Last week she sold 6 more than 3 times the number of CDs that she sold this week</u></em>

Number of CDs Kitts sold last week = 6 + 3(number of CDs that she sold this week)

x = 6 + 3y ----- eqn 1

x - 3y = 6 ------- eqn 2

<em><u>Given that Ms. Kitts sold a total of 110 CDs over the 2 weeks</u></em>

Number of CDs Kitts sold last week + number of CDs she sold this week = 110

x + y = 110 ----- eqn 3

Thus eqn 2 and eqn 3 represents the system of equations used to find x, the number of CDs she sold last week, and y, the number of CDs she sold this week

<em><u>Let us solve the above equations to find values of "x" and "y"</u></em>

Substitute eqn 1 in eqn 3

6 + 3y + y = 110

6 + 4y = 110

4y = 104

<h3>y = 26</h3>

From eqn 3,

x + 26 = 110

x = 110 - 26 = 84

<h3>x = 84</h3>

Thus number of CDs Kitts sold last week = x = 84

Number of CDs she sold this week = y = 26

6 0
2 years ago
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