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Daniel [21]
3 years ago
14

Given the following table, find the rate of change between f(-1) and f(2). x -1 0 1 2 3 f(x) -2 -1

Mathematics
2 answers:
sammy [17]3 years ago
8 0

Answer:

7 over 12

Step-by-step explanation:

The table is incomplete, so I will answer the question in general terms. The rate of change between f(-1) and f(2) is computed as follows:

rate of change = [f(2) - f(-1)]/[2 - (-1)] = [f(2) - f(-1)]/3

To complete the calculation you need to replace the values of the function at x = 2 and x = -1, and compute the result.

salantis [7]3 years ago
6 0

Answer:

[f(2) - f(-1)]/3

Step-by-step explanation:

The table is incomplete, so I will answer the question in general terms. The rate of change between f(-1) and f(2) is computed as follows:

rate of change = [f(2) - f(-1)]/[2 - (-1)] = [f(2) - f(-1)]/3

To complete the calculation you need to replace the values of the function at x = 2 and x = -1, and compute the result.

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For y = 1/3x - 4

Step-by-step explanation:


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AB = 3 + x
ICE Princess25 [194]

The given quadrilateral ABCD is a parallelogram since the opposite sides are of same length AB and DC is 4 and AD and BC is 2.

<u>Step-by-step explanation</u>:

ABCD is a quadrilateral with their opposite sides are congruent (equal).

The both pairs of opposite sides are given as AB = 3 + x , DC = 4x , AD = y + 1 , BC = 2y.

  • AB and DC are opposite sides and have same measure of length.
  • AD and BC are opposite sides and have same measure of length.

<u>To find the length of AB and DC :</u>

AB = DC

3 + x = 4x

Keep x terms on one side and constant on other side.

3 = 4x - x

3 = 3x

x = 1

Substiute x=1 in AB and DC,

AB = 3+1 = 4

DC = 4(1) = 4

<u>To find the length of AD and BC :</u>

AD = BC

y + 1 = 2y

Keep y terms on one side and constant on other side.

2y-y = 1

y = 1

Substiute y=1 in AD and BC,

AD = 1+1 = 2

BC = 2(1) = 2

Therefore, the opposite sides are of same length AB and DC is 4 and AD and BC is 2. The given quadrilateral ABCD is a parallelogram.

6 0
3 years ago
At a point on the ground 35 ft from the base of a tree, the distance to the top of the tree is 1 ft more than 3 times the height
jolli1 [7]

Answer:

Step-by-step explanation:

This is a question that uses the Pythagorean Theorem.

a = 35 feet

b = x            which is the height of the tree.

c = 3*x + 1   so we are trying to find x.  Substitute into a b and c

a^2 + b^2 = c^2

35^2 + x^2 = (3x + 1)^2        

35^2 + x^2 = 9x^2 + 6x + 1     Subtract x^2 from both sides.

35^2 = 8x^2 + 6x + 1               Subtract 35^2 from both sides.

0 = 8x^2 + 6x + 1 - 35^2

0 = 8x^2 + 6x - 1224

Does this factor?

(x + 12.75)(x - 12)

x - 12 = 0 is the only value that works.

x = 12

The tree is 12 feet high.

Note: I used the quadratic formula to solve this.

6 0
3 years ago
Read 2 more answers
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