For this, I got the equation (X+3)^2-2 or X^2+6X+7. I used this method:
First I set up an equation (X+H)^2-K, where (K, H) is the vertex. All we have to do is find where the graph reaches its minimum value (because it opens upwards), then find the x-coordinate that lies there, which is (-2,3). Substituting these value in for H and K, we get the equation <span>(X+3)^2-2 or simplified X^2+6X+7.
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Answer:
Step-by-step explanation:
Hello : let A(2,3) B(4,6)
the slope is : (YB - YA)/(XB -XA)
(6-3)/(4-2) = 3/2
an equation is : y=ax+b a is a slope
y = (3/2)x +b
the line through point (2,3) : 3 = (3/2)(2)+b
b = 0
the equation is : y =(3/2)x
Answer:
(-3,4)
(-1,4)
(-3,7)
Step-by-step explanation:
(1,1) → (1-4, 1+3) → (-3,4)
(3,1) → (3-4, 1+3) → (-1,4)
(1,4) → (1-4, 4+3) → (-3,7)
Answer:
The approximate area is A) 5.09cm²
Step-by-step explanation:
Area of a Circle = πr²
r = 1.8
Plug in our values
π(1.8cm²)
Evaluate the area of the entire circle
a = π(1.8cm²)
a = π(3.24cm)
a = 10.179cm²
Area of a sector, with the area of the circle of the sector being a = theta/360 * a
Evaluate the area of the sector
180/360*10.719cm²
0.5 * 10.179cm²
5.0895cm²
Round the value up
5.09cm²
