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Arlecino [84]
3 years ago
15

Write a loop that reads positive integers from standard input and that terminates when it reads an integer that is not positive.

After the loop terminates, it prints out, on a line by itself, the sum of all the even integers read. Declare any variables that are needed. ASSUME the availability of a variable, stdin, that references a Scanner object associated with standard input
Computers and Technology
1 answer:
kolbaska11 [484]3 years ago
6 0

Answer:

Written in Java Programming Language

import java.util.Scanner;

public class Assign{

   public static void main(String [] args)    {

   Scanner stdin = new Scanner(System.in);

   int num,sum=0;

   System.out.println("Start Inputs: ");

   num = stdin.nextInt();

   while (num>=0) {

       if(num%2== 0)

       {

       sum+=num;    

       }      

       num = stdin.nextInt();

   }

   System.out.print("Sum of even numbers: "+sum);

   

   }

}

Explanation:

I'll start my explanation from line 4

This line initializes Scanner object stdin

Scanner stdin = new Scanner(System.in);

This line declares necessary variables and initializes sum to 0

   int num,sum=0;

This line prompts user for inputs

   System.out.println("Start Inputs: ");

This line reads user inputs

   num = stdin.nextInt();

This line checks is user input is not negative (It's a loop that will be repeated continually until a negative number is inputted)

   while (num>=0) {

This line checks if user input is an even number

       if(num%2== 0)

       {

If the above condition is true, this line calculates the sum of even numbers

       sum+=num;    

       }      

This line prepares the user for next input

       num = stdin.nextInt();

   }

This line prints the calculated sum of even number; If no even number is inputted, the sum will be 0

   System.out.print("Sum of even numbers: "+sum);

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Answer:

a) P(B,A,B), P(x,y,z)

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Hence, most general unifier = {x/B , y/A , z/B }.

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Unification: Any substitution that makes two expressions equal is called a unifier.  

a) P(B,A,B), P(x,y,z)  

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Now use {y/A}  

=> P(B,A,B) , P(B,A,z)  

Now, use {z/B}  

=> P(B,A,B) , P(B,A,B}  

Hence, most general unifier = {x/B , y/A , z/B }  

b. P(x,x), Q(A,A)  

No mgu exists for this expression as any substitution will not make P(x,x), Q(A, A) equal as one function is of P and the other is of Q  

c. Older(Father(y),y), Older(Father(x),John)  

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Now use { x/John }  

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=> Q(G(x,z),G(z,x)), Q(G(x,x),G(A,B))

Use {z/x}  

=> Q(G(x,x),G(x,x)), Q(G(x,x),G(A,B))  

This is not unifiable as x cannot be bound for both A and B  

e) P(f(x), x, g(x)), P(f(y), A, z)  

Use {x/y}  

=> P(f(y), y, g(y)), P(f(y), A, z)  

Now use {z/g(y)}  

P(f(y), y, g(y)), P(f(y), A, g(y))  

Now use {y/A}  

=> P(f(A), A, g(A)), P(f(A), A, g(A))  

Thus , mgu = {x/y, z/y , y/A }.

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