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vovangra [49]
2 years ago
7

Evaluate 4z divided 7 for z=35

Mathematics
2 answers:
Vsevolod [243]2 years ago
7 0
4z / 7              for z = 35

We substitute z = 35 in 4z/7

4z/7 = 4*35 / 7 = 4*5                          7 into 35 is 5.

= 4*5 = 20

= 20

I hope this explains it.
Alex787 [66]2 years ago
4 0
Plug 35 in for z. Multiply 4 and 35 to get 140 then divide by 7 to get 20
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Answer:

The complete table is shown below.

Step-by-step explanation:

The data provided is:

Number Rolled       Observed Frequency       Relative frequency

          1                                     10                                \frac{10}{60}=\frac{1}{6}

         2                                     12                                \frac{12}{60}=\frac{1}{5}

         3                                     10                                \frac{10}{60}=\frac{1}{6}

         4                                     10                                \frac{10}{60}=\frac{1}{6}

         5                                      8                                \frac{8}{60}=\frac{2}{15}

         6                                     10                                \frac{10}{60}=\frac{1}{6}

    TOTAL                                60                                     1

The complete table is shown above.

4 0
2 years ago
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Answer:

<em>Test statistic </em>

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Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given Mean of the Population (μ) = 8.0

<em>Mean of the sample (x⁻) = 8.25</em>

Given data

                  8,9,9,8,8,9,8,7

Given sample size  n= 8

Given sample standard deviation(S) = 0.661

<u><em>Step(ii):-</em></u>

<em>Null hypothesis : H:  (μ) = 8.0</em>

<em>Alternative Hypothesis :H:(μ) > 8.0</em>

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<em>Test statistic </em>

<em>               </em>t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }<em></em>

<em>              </em>t = \frac{8.25 -8.0}{\frac{0.661}{\sqrt{8} } }<em></em>

<em>            t =  1.076</em>

<em>Critical value </em>

<em>                    t₍₇,₀.₀₅₎   = 2.3646</em>

<em>The calculated value   t =  1.076 < 2.3646 at 0.05 level of significance</em>

<em>Null hypothesis is accepted</em>

<em>Test the hypothesis that the true mean quiz score is 8.0 against the alternative that it is not greater than 8.0</em>

<em></em>

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Answer:

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Step-by-step explanation:

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