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3 years ago

Can someone pls help im new to this

Mathematics

1 answer:

Serggg [28]3 years ago

3 0

Answer:

Step-by-step explanation:

$\frac{-10}{-2} \\\\5$

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Simplest form of the expression -2x2(x – 5) + x(2x2 – 10x) + x is

Andrei [34K]

You first simplify the expression using PEMDAS
-2x^3-10x^2+2x^3-10x^2+x
then combine like terms,
(-2x^3+2x^3), (-10x^2-10x^2), x
cancels out^
so the answer would be -20x^2+x

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3 years ago

A governor of state A earns 53,435 more than the governor of state B. If the total of their salaries is 290,395, find the salari

Pepsi [2]

Let A and B represent the governor's salaries of states A and B, respectively.

A - B = 53,435
A +B = 290,395

Add these two equations to eliminate B.
2A = 343,830
A = 171,915

B = A -53,435 = 118,480

The governor of state A has a salary of 171,915.
The governor of state B has a salary of 118,480.

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4 years ago

How do you write 13.6% as a decimal or mixed number

astraxan [27]

Answer: As a decimal it would be .136. You can write it as a decimal by dividing by 100 as you would need to get this total by multiplying by 100. Just reverse the steps into making a percentage.

Example: 70 out of 200.

You'd do 70 divided by 200 and get .35.

After, you would multiply by 100 to turn it into a percentage.

If you want to turn it into a decimal divide by 100.

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3 years ago

Question text You have just won the lottery. The Lottery Corporation offers you two options: 1. a lump-sum payment of $400,000,

igomit [66]

Use present value equation.
If present value of annuity equals 400,000, then you are indifferent.

$PV = A(v + v^2 + ...v^{20}) \\ \\ PV = A\frac{v(1-v^{20})}{1-v}$

where v = 1/(1+r) and A = annual payment = 800,000/20 = 40,000

PV = 400,000
After subbing in the numbers, the equation is:
$10 = \frac{v(1-v^{20})}{1-v} \\ \\ 10 - 10v = v - v^{21} \\ \\ v^{21} - 11v+10 = 0 \\ \\ v = 0.928034 \\ \\ \frac{1}{1+r} = 0.928034 \\ \\ r = 0.0775$

Therefore at interest rate of about 7.75% you are indifferent.

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4 years ago

ASAP!!! Use the pythagorean theorem to prove that the point (√2/2, √2/2) lies on the unit circle. I need setup, explination, ans

docker41 [41]

Answer:

In brief, apply the pythagorean theorem to show that the distance between the point $(\sqrt{2}/2,\sqrt{2}/2)$ and the origin is $1$ .

Step-by-step explanation:

The pythagorean theorem can give the distance between two points on a plane if their coordinates are known.

A point is on a circle if its distance from the center of the circle is the same as the radius of the circle.

On a cartesian plane, the unit circle is a circle

centered at the origin $(0,0)$
with radius $1$ .

Therefore, to show that the point $(\sqrt{2}/2,\sqrt{2}/2)$ is on the unit circle, show that the distance between $(\sqrt{2}/2,\sqrt{2}/2)$ and $(0,0)$ equals to $1$ .

What's the distance between $(\sqrt{2}/2,\sqrt{2}/2)$ and $(0,0)$ ?

$\displaystyle \sqrt{\left(\frac{\sqrt{2}}{2}-0}\right)^{2} + \left(\frac{\sqrt{2}}{2}-0\right)^{2}} = \sqrt{\frac{1}{2} + \frac{1}{2}}= \sqrt{1}= 1$ .

By the pythagorean theorem, the distance between $(\sqrt{2}/2,\sqrt{2}/2)$ and the center of the unit circle, $(0,0)$ , is the same as the radius of the unit circle, $1$ . As a result, the point $(\sqrt{2}/2,\sqrt{2}/2)$ is on the unit circle.

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3 years ago