Graph attached. To graph by hand find the values at 1 and 3 by plugging it into the original function and drawing a line between the two.
2(1)-2 = 0 Point (1,0)
2(3)-2 = 4 Point (3,4)
3/4 I think, but it also depends on the order of the birth, so it could be 7/8 as well.
4n/4n-4 × n-1/n+1
= 4n(n-1)/(4n-4)(n+1)
= (4n^2 - 4n)/(4n^2 + 4n - 4n-4)
= (4n^2 - 4n)/(4n^2 - 4)
= 4(n^2 - n)/4(n^2 - 1)
=(n^2 - n)/(n^2 - 1)
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