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vredina [299]
3 years ago
8

A class has 4 boys and 10 girls. What is the ratio in the simplest form that compares a number of boys to a total number of stud

ents?
need the right answer
Mathematics
1 answer:
sergejj [24]3 years ago
6 0

Answer:

4 to 14 should be the right answer

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Identify the class midpoints for the given frequency distribution.
german

Answer:

s

Step-by-step explanation:

8 0
3 years ago
To complete a task in 15 days, a company has 4 people each working 8 hours a day. The company
Klio2033 [76]

Answer:

Let's suppose that each person works at an hourly rate R.

Then if 4 people working 8 hours per day, a total of 15 days to complete the task, we can write this as:

4*R*(15*8 hours) = 1 task.

Whit this we can find the value of R.

R = 1 task/(4*15*8 h) = (1/480) task/hour.

a) Now suppose that we have 5 workers, and each one of them works 6 hours per day for a total of D days to complete the task, then we have the equation:

5*( (1/480) task/hour)*(D*6 hours) = 1 task.

We only need to isolate D, that is the number of days that will take the 5 workers to complete the task:

D = (1 task)/(5*6h*1/480 task/hour) = (1 task)/(30/480 taks) = 480/30 = 16

D = 16

Then the 5 workers working 6 hours per day, need 16 days to complete the job.

b) The assumption is that all workers work at the same rate R. If this was not the case (and each one worked at a different rate) we couldn't find the rate at which each worker completes the task (because we had not enough information), and then we would be incapable of completing the question.

4 0
3 years ago
PLEASE HELP ME!!!
Harman [31]
Send a better photo or tell me what I’m suppose to be answering
8 0
3 years ago
Meg is 6 years older than Victor. Meg's age is 2 years less than five times Victor's age. The equations below model the relation
Verdich [7]

Since no possible correct method is posted, I will suggest a couple.

Method 1: guess and check

Works well for simple problems involving integers like this one.

Victor's age must be zero or greater than one, say one.

Guess v=1, find m=v+6=7, check m=5v-2=5-2=3 no good.

we need to make v bigger

Guess v=2, find m=v+6=2+6=8, check m=5v-2=5*2-2=8 ✔

So v=2, m=8.

Method 2:

Solve the system of two equations.

since the left-hand sides is m in both equations, and since m=m, we just have to equate the right-hand sides to solve for v.

5v-2=v+6

Solve for v

5v-v = 6+2

4v=8

v=2,

so again, v=2, m=v+6=2+6=8.

6 0
3 years ago
Estefani‘s house is at point E (3,-2) and Jasmin’s house is at point J (-5,3). Jasmin’s house is the Mid-point of Estefani’s hou
iren [92.7K]

The formula for midpoint is

(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2})

Look at the image below to see the line segment of Estefani's (A), Jasmin's (M), and Preston's (B) houses. Keep in mind that the segment shown below is not accurate in regards to how the line segment formed by Estefani's, Jasmin's, and Preston's houses. It is simply there so you can picture the segment better.

In this case:

x_{1} =3\\x_{2} =unknown\\y_{1} =-2\\y_{2} =unknown

^^^Plug in these number into the formula given above...

(\frac{3+x}{2}, \frac{-2 + y}{2})

To find what x is (a coordinate of Preston's house) you must take the x-value part of the midpoint equation (\frac{3+x}{2}) and set it equal to the x-value of the midpoint (-5). Then you must solve for x:

\frac{3+x}{2} = -5

3 + x = -5 * 2

3 + x = -10

x = -10 - 3

x = -13

To find what y is (a coordinate of Preston's house) you must take the  y-value part of the midpoint equation(\frac{-2 + y}{2}) and set it equal to the y-value of the midpoint (3). Then you must solve for y:

\frac{-2 + y}{2} = 3

-2 + y = 3 * 2

-2 + y = 6

y = 6 + 2

y = 8

The coordinate of Preston's house is:

(-13, 8)

Hope this helped!

~Just a girl in love with Shawn Mendes

7 0
3 years ago
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