Ok so assuming the board only has 4 spaces to land on (A,B,C,D) all we need to do is weight the probability,
1/4 x 1/4 x 1/4 x 1/4 x 1/4 = 1/1024
To solve I put the number of favorable outcomes over the number of total outcomes, in this case we had 1 favorable outcome each time and a constant of 4 possible outcomes.
What are the answers but I think it becauenhe woudny get pregnant
8 chairs, 8 squared is 64,ie the amount of chairs in total
Answer:
C. 8, H. 6x^2+43x+55
Step-by-step explanation:
You're looking for a value that will make x-2=6, since you add exponents. So W^8/W^-2 is equal to 1/W^6. Since 8-2=6.
A= length * width
(2x+11)(3x+5), foil it out by taking 2x(3x+5), then 11(3x+5).
6x^2+10x+33x+55, combine like terms
6x^2+43x+55
Answer:
P(AUB)'=2/15
Step-by-step explanation:
According to the Question,
- Given That, A and B be two independent events. If P(A)=3/5 and P(B')=1/3.
So, P(B)=1-P(B') ⇒ P(B)=1-(1/3) ⇔ P(B)=2/3
- The Product Rule of Probability says For independent events P(A∩B)=P(A)×P(B)
P(A∩B)=3/5 × 2/3 ⇒ P(A∩B)=2/5
- We know, P(AUB)=P(A)+P(B)-P(A∩B)
Thus, P(AUB)= 3/5 + 2/3 - 2/5
P(AUB)=1/5 + 2/3
P(AUB)=(3+10)/15 ⇔P(AUB)=13/15
- Now, The Value Of P(AUB)'=1-P(AUB) ⇔ 1 - 13/15 ⇒ P(AUB)'=2/15
