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N76 [4]
3 years ago
15

Decide whether the equation is a function, not a function, linear but not a function, or a linear function. Choose the best opti

on.
8x-3y=-2
а
b
Function
Not a Function
Linear But Not a Linear Function
Linear Function
С
d
Mathematics
2 answers:
zalisa [80]3 years ago
6 0

Answer:

Linear Function

Step-by-step explanation:

8x-3y = -2

-3y = 8x-2

3y = -8x+2

y = \frac{-8x+2}{3}

y = -\frac{8}{3}x+\frac{2}{3}

Linear Function

Lostsunrise [7]3 years ago
5 0
The answer is function
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Answer:

C.

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Step-by-step explanation:

You have the quadratic function 2x^2-x+1=0 to find the solutions for this equation we are going to use Bhaskara's Formula.

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Then we have  2x^2-x+1=0  where a=2, b=-1 and c=1. Applying the formula:

x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}\\\\x_1=\frac{-(-1)+\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_1=\frac{1+\sqrt{1-8} }{4}\\\\x_1=\frac{1+\sqrt{-7} }{4}\\\\x_1=\frac{1+\sqrt{(-1).7} }{4}\\x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}

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x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}\\\\x_1=\frac{1+i.\sqrt{7}}{4}\\\\x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i

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x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}\\\\x_2=\frac{-(-1)-\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_2=\frac{1-i.\sqrt{7} }{4}\\\\x_2=\frac{1}{4}-(\frac{\sqrt{7}}{4})i

Then the correct answer is option C.

x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i and x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i

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