Answer:
y=1/8x+6
Step-by-step explanation:
y-y1=m(x-x1)
y-9=1/8(x-24)
y=1/8x-24/8+9
y=1/8x-3+9
y=1/8x+6
Answer:
Step-by-step explanation:
Since there are 20 students, this will be the denominator.
Now, to find how many students have a dog and a cat, you need to subtract all the numbers with 20. The leftover number will be the amount of students.
7+8+8=23
23-20=3
So, there are 3 students who have a dog and a cat.
So, the fraction will be
Answer:
y= -2x-22.
Step-by-step explanation:
1) the slope-interception common form is y=s*x+i, where 's' and 'i' are the slope and interception, unknown numbers;
2) if x₁= -3; y₁= -16, and s=-2, then the equation of the required line can be written in the point-interception form y-y₁=s(x-x₁); ⇔ y+16= -2(x+3);
3) the required equation in slope-interception form is:
y+16= -2x-6; ⇒ y= -2x-22.
note, the provided solution is not the only and shortest way.
If a(2) = 0, then k=2. The product of the zeros is
(2)*(3)*(6)*(-3) = -108
The absolute value of the product of zeros of a(t) is 108.
The total weight of candies is unknown. Let x = the total weight of candies.
"One student ate 3/20 of all candies and another 1.2 lb":
The first student ate (3/20)x plus 1.2 lb which is 0.15x + 1.2.
"The second student ate 3/5 of the candies and the remaining 0.3 lb."
The second student ate (3/5)x and 0.3 lb which is 0.6x + 0.3.
Altogether the 2 students ate 0.15x + 1.2 + 0.6x + 0.3.
That was all the amount of candies, so that sum equals x.
0.15x + 1.2 + 0.6x + 0.3 = x
Now we solve the equation for x to find what the total amount of candies was.
0.75x + 1.5 = x
-0.25x = -1.5
x = 6
The total amount of candies was 6 lb.
The first student ate 0.15x + 1.2 = 0.15(6) + 1.2 = 0.9 + 1.2 = 2.1, or 2.1 lb of candies.
The second student ate 0.6x + 0.3 = 0.6(6) + 0.3 = 3.6 + 0.3 = 3.9, or 3.9 lb of candies.
Answer: The first student ate 2.1 lb of candies, and the second student ate 3.9 lb of candies.
