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3 years ago

Idc about giving away my points...How about 20+ Points for explanation & Correct answer

Mathematics

1 answer:

kramer3 years ago

7 0

Answer:

The answer to the problem is 36.

Step-by-step explanation:

As seen in the bottom function, x has been replaced with 2. So now we have the new equation of f(2) = 6^2

f(2) = 6^2

6*6 = 36

f(2) = 36

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3 years ago

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Evaluate the expression when a=-18 and b= -6<br> b to the power of 2 divided by a plus 4

tiny-mole [99]

Answer:

a wanna

Step-by-step explanation:

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(5) Rhea ran 6 laps on a track. Each lap is 200 yards. Rhea's average speed for

sashaice [31]

Answer:

72 yd / min

Step-by-step explanation:

The first thing is to fully calculate the distance traveled, each lap is 200 yards and how 6 laps would be:

200 * 6 = 1200

Now, let's divide the race into how the statement tells us:

1200 * 2/3 = 800

1200 * 1/3 = 400

That is, in the first 800 yards it goes to 80 yd / min and then in the remaining 400 yards it goes to 60 yd / min, let's calculate the time Rhea lasted:

800/80 = 10 min

400/60 = 6,667 min

Which means that in total it would be:

10 + 6,667 = 16,667

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1200 / 16,667 = 72

Therefore the average Rhea speed was 72 yd / min

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3 years ago

Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle

Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x+3)^{2} +(y-4)^{2}=r^{2}$

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

$r=\sqrt{(2-4)^{2}+(-6+3)^{2}}$

$r=\sqrt{(-2)^{2}+(-3)^{2}}$

$r=\sqrt{13}\ units$

The equation of the circle is equal to

$(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}$

$(x+3)^{2} +(y-4)^{2}=13$

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

$(10+3)^{2} +(4-4)^{2}=13$

$(13)^{2} +(0)^{2}=13$

$169=13$ -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x-1)^{2} +(y-3)^{2}=r^{2}$

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

$r=\sqrt{(6-3)^{2}+(2-1)^{2}}$

$r=\sqrt{(3)^{2}+(1)^{2}}$

$r=\sqrt{10}\ units$

The equation of the circle is equal to

$(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}$

$(x-1)^{2} +(y-3)^{2}=10$

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

$(11-1)^{2} +(5-3)^{2}=10$

$(10)^{2} +(2)^{2}=10$

$104=10$ -----> is not true

therefore

The point is not on the circle

The statement is false

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3 years ago

PLEASE HELP

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After plotting the data from the table, with the number of times sick per year as a function of the number of apples eaten per week, I can conclude that there is no definite correlation between the two variables. This is because the data points do not have a good fit with any trend, meaning the R-squared value is low. Thus, the number of apples eaten per week has no significant effect on the number of times the people listed get sick per year.

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3 years ago