Answer:
or 
Given expression:
Simplify it in steps below:
<u>Used properties:</u>
<h3><u>Answers in Step-By-Step</u></h3>
Step-by-step explanation:
A; the admission price is $15
For adults its 2x
For students its x
and for children under 3 years old its 1/2x
to find the weekend money replace "x" with 15 as the money.
Adults: 2 * 15
students: 15
infants: 1/2 * 15
Do the math
2 * 15 = 30
15 = 15
1/2 * 15 = 7.5
B; A group of 4 adults, 5 students, and 2 children under the age of 3 visits the theme park on Sunday.
for each adult is $30
each student is $15
and children under 3 is $7.50
Do the math
30 * 4 = 120
15 * 5 = 75
2 * 7.5 = 15
120 + 75 + 15 = $210
C; If a student's weekday cost's $18, find the total admission cost that group B) has to pay.
Adult: 18 * 2
Student: 18
infant: 1/2 * 18
do the math
18 * 2 = 36
18 = 18
1/2 * 18 = 9
each adult is $36
each Student is $18
each infant is $9
4 adults, 5 students, 2 children under 3
4 * 36 = 144
5 * 18 = 90
9 * 2 = 18
144 + 90 + 18 = 252
The total would come out to $252
Answer:
total amount paid = 32.5 + 28.9 + 24.95 = 86.35
20% of the total amount paid = 0.2 * 86.35 = 17.27
you tip 17.25$
Answer:
The statement is true for every n between 0 and 77 and it is false for 
Step-by-step explanation:
First, observe that, for n=0 and n=1 the statement is true:
For n=0: 
For n=1: 
From this point we will assume that 
As we can see, 
and 
. Then,
Now, we will use the formula for the sum of the first 4th powers:
Therefore:
and, because 
,
Observe that, because 
and is an integer,
In concusion, the statement is true if and only if n is a non negative integer such that 
So, 78 is the smallest value of n that does not satisfy the inequality.
Note: If you compute 
for 77 and 78 you will obtain:
\left[a _{3}\right] = \left[ \frac{ - b^{2}}{6}+\frac{\frac{ - b^{4}}{3}+\left( \frac{-1}{3}\,i \right) \,\sqrt{3}\,b^{4}}{2^{\frac{2}{3}}\,\sqrt[3]{\left( -1296 - 432\,b^{2} - 16\,b^{6}+\sqrt{\left( 1679616+1119744\,b^{2}+186624\,b^{4}+41472\,b^{6}+13824\,b^{8}\right) }\right) }}+\frac{\frac{ - \sqrt[3]{\left( -1296 - 432\,b^{2} - 16\,b^{6}+\sqrt{\left( 1679616+1119744\,b^{2}+186624\,b^{4}+41472\,b^{6}+13824\,b^{8}\right) }\right) }}{24}+\left( \frac{1}{24}\,i \right) \,\sqrt{3}\,\sqrt[3]{\left( -1296 - 432\,b^{2} - 16\,b^{6}+\sqrt{\left( 1679616+1119744\,b^{2}+186624\,b^{4}+41472\,b^{6}+13824\,b^{8}\right) }\right) }}{\sqrt[3]{2}}\right][a3]=⎣⎢⎢⎢⎢⎡6−b2+2323√(−1296−432b2−16b6+√(1679616+1119744b2+186624b4+41472b6+13824b8))3−b4+(3−1i)√3b4+3√224−3√(−1296−432b2−16b6+√(1679616+1119744b2+186624b4+41472b6+13824b8))+(241i)√33√(−1296−432b2−16b6+√(1679616+1119744b2+186624b4+41472b6+13824b8))⎦⎥⎥⎥⎥⎤
