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Answer:
Step-by-step explanation:
Given the following question:
To estimate by the nearest thousand, we have to look at the thousand's place value and then look at the number next to it, to see if it's greater than five.
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<span>-6x^4y^5 - 15x^3y^2 + 9x^2y^3
</span>-6x^4y^5 = -2, 3, x, x, x, x, y, y, y, y, y
15x^3y^2 = -5, 3 x, x, x, y, y
9x^2y^3 = 3, 3 x, x, y, y, y
Each group has a 3 in common and each group has 2 x in common and each group has 2 y in common so the GCF = -3x^2y^2
Divide that out and we get
</span>-6x^4y^5 = -2, 3, x, x, x, x, y, y, y, y, y
15x^3y^2 = -5, 3 x, x, x, y, y
9x^2y^3 = 3, 3 x, x, y, y, y
Each group has a 3 in common and each group has 2 x in common and each group has 2 y in common so the GCF = -3x^2y^2
Divide that out and we get