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3 years ago

Hiw do I Graph the line y=-3

Mathematics

2 answers:

Lostsunrise [7]3 years ago

5 0

Answer:

Step-by-step explanation:

motikmotik3 years ago

5 0

Answer:

The graph below should help:

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Find the slope of the line that goes through the given points (8,5) (6,7)

vazorg [7]

To find the slope of a line that goes through given points with known coordinates, you divide the subtraction of the y of the second point minus the y of the first point, by the subtraction of the x of the second point minus the x of the first point:
m = (yB-yA) / (xB-xA)

Let A(8,5) and B(6,7).
With yB = 7; yA = 5; xB = 6; xA = 8
m = (7-5) / (6-8)
m = 2/-2
m = -1

So the slope of the line that goes through the given points (8,5) and (6,7) is m = -1.

I've added a pic of the line with both points under the answer.

Hope this Helps! :)

4 0

3 years ago

Please help me!!!!!!!!!!!!!!!

Ainat [17]

r = 7.53 so d = 2r = 2(7.53) = 15.06 cm

Area of square = d^2 / 2 = (15.06)^2 / 2 = 113.41 cm^2

Area of circle = 3.14 (7.53)^2 = 178.04 cm^2

Area of yellow region = Area of circle - Area of square

Area of yellow region = 178.04 cm^2 - 113.41 cm^2

Area of yellow region =64.63 cm^2 = 64.6 cm^2 (nearest tenth)

Answer

64.6 cm^2

7 0

3 years ago

Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,

sweet [91]

Answer:

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

$f'' = x - \frac{3}{2}$

$f' = \int {\left(x-\frac{3}{2}\right) } \, dx$

$f' = \int {x} \, dx -\frac{3}{2}\int \, dx$

$f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C$ , where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative ( $f'(4) = 1$ ):

$1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C$

$C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)$

$C = -1$

The first derivative is $y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1$ , and the particular solution is found by integrating one more time and using the initial condition ( $f(0) = 0$ ):