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3 years ago

Solve for x under the assumption that x > 0. Enter your answer in interval notation using grouping symbols.

1 answer:

3 0

<span>Starting with x−24/x<10 multiply everything by x. x^2-24<10x Subtract 10x from both sides. x^2-10x-24 < 0 Factor. (x-12)(x+2) < 0 (x+2) is always positive since x > 0, but (x-12) is negative when x is a value between 0 and 12. This negative value for (x-12) satisfies that the left side is less than 0. Thus the solution set for x is (0,12).</span>

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Which equation shows the quadratic formula used correctly to solve 5x2 + 3x – 4 = 0 for x?

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Answer:

$x=\frac{-3\pm\sqrt{(3)^2-4(5)(-4)}}{2(5)}$

Therefore, Option 1 is correct.

Step-by-step explanation:

We have been given the quadratic equation:

$5x^2+3x-4=0$

If we compare it will general quadratic equation which is: $ax^2+bx+c=0$

Here, a=5,b=3 and c= -4.

Now, we will use the formula:

And then $x=\frac{-b\pm\sqrt{D}}{2a}$

Where, $D=b^2-4ac$

$x=\frac{-3\pm\sqrt{(3)^2-4(5)(-4)}}{2(5)}$

Therefore, Option 1 is correct.

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