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3 years ago

Solve for x under the assumption that x > 0. Enter your answer in interval notation using grouping symbols.

1 answer:

3 0

<span>Starting with x−24/x<10 multiply everything by x. x^2-24<10x Subtract 10x from both sides. x^2-10x-24 < 0 Factor. (x-12)(x+2) < 0 (x+2) is always positive since x > 0, but (x-12) is negative when x is a value between 0 and 12. This negative value for (x-12) satisfies that the left side is less than 0. Thus the solution set for x is (0,12).</span>

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Two cones have a radius of 2 cm. The height of one cone is 8 cm. The other cone is 1 4 14 that height. Which of these statements

MAXImum [283]

Hi there!
The correct answer (the statement that is not true): The volume of the smaller cone cannot be determined because it’s height is unknown.
Hope this helps and have a good day :) !
~Angel

4 0

3 years ago

8. By one estimate, 3% of all Siberian Husky puppies are born with two different

suter [353]

Answer:

Step-by-step explanation:

Mux= np

sigmax= $\sqrt{np(1-p)\\$

Mean = 50(.65)

Standard Deviation = $\sqrt{1.5(1-.03)}$

8 0

3 years ago

We know 4 times 9 = 36

omeli [17]

Hello!

So, 9 is a multiple of 36, we know that much.
36 is NOT a factor of four.
9 is a factor of 36.
So, check the first box and the third box.

Have a wonderful day! :)

-L

6 0

3 years ago

Read 2 more answers

Write .008% as a decimal

lions [1.4K]

0.008%=0.008/100=0.00008

5 0

3 years ago

What is the z-score of a newborn who weighs 4,000 g?.

vagabundo [1.1K]

The z-score of the considered newborn having 4,000 g weight is $\dfrac{4000 - \mu}{\sigma}$

<h3>How to get the z scores?</h3>

If we've got a normal distribution, then we can convert it to standard normal distribution and its values will give us the z score.

If we have

$X \sim N(\mu, \sigma)$

(X is following normal distribution with mean $\mu$ and standard deviation $\sigma$ )

then it can be converted to standard normal distribution as

$Z = \dfrac{X - \mu}{\sigma}, \\\\Z \sim N(0,1)$

(Know the fact that in continuous distribution, probability of a single point is 0, so we can write

$P(Z \leq z) = P(Z < z) )$

Also, know that if we look for Z = z in z tables, the p value we get is

$P(Z \leq z) = \rm p \: value$

For the considered case, the statement in the problem is missing the mean weight of the newborn and standard deviation of the data set of weights of newborn.

Thus, for them, we can consider variables in place of their actual values.

Let we have:

X = weights of newborns for some considered system (in grams)
$\mu$ = mean weight of newborns (in grams)
$\sigma$ = standard deviation of the data set of weights of newborns

Then, the z-score for X = 4000 is

$z = \dfrac{x - \mu}{\sigma} = \dfrac{4000 - \mu}{\sigma}$

Thus, the z-score of the considered newborn having 4,000 g weight is $\dfrac{4000 - \mu}{\sigma}$

Learn more about z-scores here:

brainly.com/question/13299273

3 0

2 years ago