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viktelen [127]
3 years ago
5

Can you help me with numbers 20-22 please a lot of points

Mathematics
1 answer:
arsen [322]3 years ago
6 0
We could find the slope with this formula
m = (y₂ - y₁)/(x₂ - x₁)
with (x₁,y₁) and (x₂,y₂) are the points that is located on the line.


NUMBER 20
Given:
(x₁,y₁) = (-2,3)
(x₂,y₂) = (7,-4)

Solution:
Input the points to the formula
m = (y₂ - y₁) / (x₂ - x₁)
m = (-4 - 3) / (7 - (-2))
m = -7 / (7+2)
m = -7/9

The slope of the line is -7/9


NUMBER 21
Given:
(x₁,y₁) = (-6,-1)
(x₂,y₂) = (4,1)

Solution:
Input the points to the formula
m = (y₂ - y₁) / (x₂ - x₁)
m = (1-(-1)) / (4 -(-6))
m = (1+1) / (4+6)
m = 2/10
m = 1/5

The slope of the line is 1/5


NUMBER 22
Given:
(x₁,y₁) = (-9,3)
(x₂,y₂) = (2,1)

Solution:
Input the points to the formula
m = (y₂ - y₁) / (x₂ - x₁)
m = (1 - 3) / (2 - (-9))
m = -2 / (2 + 9)
m = -2/11

The slope of the line is -2/11
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The figure shown in the picture is a rectangular shape that is missing a triangular piece. To determine the area of the figure you have to determine the area of the rectangle and the area of the triangular piece, then you have to subtract the area of the triangle from the area of the rectangle.

The rectangular shape has a width of 12 inches and a length of 20 inches. The area of the rectangle is equal to the multiplication of the width (w) and the length (l), following the formula:

A=w\cdot l

For our rectangle w=12 in and l=20 in, the area is:

\begin{gathered} A_{\text{rectangle}}=12\cdot20 \\ A_{\text{rectangle}}=240in^2 \end{gathered}

The triangular piece has a height of 6in and its base has a length unknown. Before calculating the area of the triangle, you have to determine the length of the base, which I marked with an "x" in the sketch above.

The length of the rectangle is 20 inches, the triangular piece divides this length into three segments, two of which measure 8 inches and the third one is of unknown length.

You can determine the value of x as follows:

\begin{gathered} 20=8+8+x \\ 20=16+x \\ 20-16=x \\ 4=x \end{gathered}

x=4 in → this means that the base of the triangle is 4in long.

The area of the triangle is equal to half the product of the base by the height, following the formula:

A=\frac{b\cdot h}{2}

For our triangle, the base is b=4in and the height is h=6in, then the area is:

\begin{gathered} A_{\text{triangle}}=\frac{4\cdot6}{2} \\ A_{\text{triangle}}=\frac{24}{2} \\ A_{\text{triangle}}=12in^2 \end{gathered}

Finally, to determine the area of the shape you have to subtract the area of the triangle from the area of the rectangle:

\begin{gathered} A_{\text{total}}=A_{\text{rectangle}}-A_{\text{triangle}} \\ A_{\text{total}}=240-12 \\ A_{\text{total}}=228in^2 \end{gathered}

The area of the figure is 228in²

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Step-by-step explanation:

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2 years ago
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melisa1 [442]

Answer:

sin O=\dfrac{3\sqrt{13}}{13}\\cos O=\dfrac{2\sqrt{13}}{13}\\tan O=\dfrac{3}{2}

Step-by-step explanation:

If the point (2,3) is on the terminal side of an angle in standard position.

Adjacent of O, x=2,

Opposite of O, y=3

Next, we determine the hypotenuse, r using Pythagoras Theorem.

Hypotenuse =\sqrt{Opposite^2+Adjacent^2} \\r=\sqrt{3^2+2^2} \\r=\sqrt{13}

Therefore:

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3 years ago
Help! (Math and area!!)
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Answer:

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2.) Rhombus is<u> ½ × d1 × d2. (Which is option A)</u>

3.) Trapezoid is <u>½(b 1+b 2)h or (b1 + b2)h/2 (Which is option B)</u>

4.) Parallelogram is <u>base x height (Which is option D)</u>

Step-by-step explanation:

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