Answer: 11am
Step-by-step explanation:
To solve this, we have to calculate the lowest common multiple of 20 and 30. This will be:
20 = 20, 40, 60, 80, 100
30 = 30, 60, 90, 120, 150.
Here, the lowest common multiple is 60.
Therefore, we add 60 minutes to 10am. This will be:
= 10am + 1 hour
= 11 am
The next time that both buses leave at the same time would be 11am
Sqrt (53) = 10 * sqrt (0.53)
0.53 = 64/121
sqrt (0.53) = sqrt (64)/ sqrt (121) = 8/11 = 0.7273
Therefore sqrt (53) = 10 * 0.7273 = 7.27
sqrt (108) = 10 * sqrt (1.08)
sqrt (1.08) = sqrt (676/625) = 26/25 = 1.04
Therefore sqrt (108) = 10 * 1.04 = 10.4
sqrt (128) = 10 * sqrt (1.28)
sqrt (1.28) = sqrt (289/225) = 17/15 = 1.133
Therefore sqrt (108) = 10 * 1.133 = 11.33
If we assume the given segments are those from the vertices to the point of intersection of the diagonals, it seems one diagonal (SW) is 20 yards long and the other (TR) is 44 yards long. The area (A) of the kite is half the product of the diagonals:
... A = (1/2)·SW·TR = (1/2)·(20 yd)·(44 yd)
... A = 440 yd²
Well Those are variables and it is using the Distributive property to solve. For example P(a+b) simplify P*a + P*b.
