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3 years ago

Using synthetic division, find (x^4 − 2) ÷ (x + 1).

Mathematics

1 answer:

damaskus [11]3 years ago

3 0

-1 is the rest, because its degree is smaller than that of the divisor and therefore can not continue dividing.
x ^ 3 - x ^ 2 + x -1 is the quotient.
I attach the solution

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A smoke jumper jumps from a plane that is 1700 ft above the ground. The function y = -16t2 + 1700 gives the jumper's height y in

lakkis [162]

Answer: (A) 6.6 sec (B) 6.89 sec

Step-by-step explanation:

y = -16t² + 1700

1000 = -16t² + 1700

-1700 -1700

-700 = -16t²

÷-16 ÷-16

43.75 = t²

√43.75 = √t²

6.6 = t

***********************************

y = -16t² + 1700

940 = -16t² + 1700

-1700 -1700

-760 = -16t²

÷-16 ÷-16

47.5 = t²

√47.5 = √t²

6.89 = t

4 0

3 years ago

What is the best estimate for the number of people in line at 7.A.M

Keith_Richards [23]

We have been given the equation

$y=-5.131x^2+31.821x-3.333$

It represents the number of people standing to catch a commuter train x hours after 5 A.M.

Now, in order to find the number of people in line at 7 a.m. , we need to substitute x= 2 in the above equation.

$y(2)=-5.131(2)^2+31.821(2x)-3.333\\y(2)= 39.785 \approx 40$

Therefore, the number of people in the line at 7 a.m. is 40

D id the correct option.

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3 years ago

What is the solution to the following equation? 17 n -23n + 11.5n = 44

faltersainse [42]

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

n = 8

Step-by-step explanation:

Have a nice day! I hope this helps!

5 0

3 years ago

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Sec squared 55 - tan squared 55

sergejj [24]

Answer:

sec squared 55 – tan squared 55 = 1

Explanation:

Given, sec square 55 – tan squared 55

We know that,

$\sec \Theta=\frac{\text {hypotenuse}}{\text {base}}$

And,

$\tan \theta=\frac{\text { perpendicular }}{\text { base }}$

where Ө is the angle

Substituting the values

$\left(\frac{\text {hypotenuse}}{\text {base}}\right)^{2}-\left(\frac{\text { perpendicular }}{\text {base}}\right)^{2}$

Solving,

$\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}$

According to Pythagoras theorem,

$\text { (hypotenuse) }^{2}-\text { (perpendicular) }^{2}=(\text { base })^{2}$

Putting this in the equation;

squared 55 - tan squared 55 =

$\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}=\frac{(\text {base})^{2}}{(\text {base}) *(\text {base})}=1$

Therefore, sec squared 55 – tan squared 55 = 1

6 0

3 years ago

3 to the power of 2 + 4 to the power of 2

julia-pushkina [17]

Answer:

Step-by-step explanation:

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5 0

3 years ago

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