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3 years ago

So I’m doing my homework and I don’t know 3 2/3 + 5/4

Mathematics

1 answer:

vivado [14]3 years ago

3 0

Answer:

4 11/12

Step-by-step explanation:

4 x 2/3 = 8/12

3 x 5/4 = 15/ 12

8/12 + 15/12 = 23/12 = 1 11/12 + 3 = 4 11/12

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Help me please please please

Archy [21]

Answer:

24 $in^{3}$

Step-by-step explanation:

volume formula= l x w x h

Box A:

4 x 3 x 4 = 48

Box B: 48/2 = 24

3 0

2 years ago

-17x + 2 +3x^2 + 2x^3 divided by x-2

Stells [14]

Answer:

2x^2+7x-3

remainder is -4

Step-by-step explanation:

Check the image

6 0

3 years ago

line pass through the line (-3, -7.5)tahila determined that the equation of line n is y=0.5x explain the error tahila made while

Tasya [4]

The equation of the line will be (assuming the y-intercept equal to zero):

y = 2.5*x

<h3>What is Tahila's mistake?</h3>

We know that we have a linear equation of the form:

y = a*x + b

Such that we know that the line passes through (-3, -7.5), notice that the proposed equation is:

y = 0.5*x

If you evaluate that in -3, you get:

y = 0.5*-3 = -1.5

So this line does not pass through (-3, -7.5).

If we assume that b = 0 in the linear equation, then we can find the value of a as:

-7.5 = a*-3

a = 7.5/3 = 2.5

Then the linear equation is:

y = 2.5*x

If you want to learn more about linear equations:

brainly.com/question/1884491

#SPJ1

4 0

2 years ago

We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the stu

Molodets [167]

Answer:

The correct option is (c).

Step-by-step explanation:

The complete question is:

The data for the student enrollment at a college in Southern California is:

Traditional Accelerated Total

Math-pathway Math-pathway

Female 1244 116 1360

Male 1054 54 1108

Total 2298 170 2468

We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the student is female. Which of the following pairs of probabilities is not a useful comparison?

a. 1360/2468 and 116/170

b. 170/2468 and 116/1360

c. 1360/2468 and 170/2468

Solution:

If two events <em>A</em> and <em>B</em> are independent then:

$P(A|B)=P(A)\\\\\&\\\\P(B|A)=P(B)$

In this case we need to determine whether a student enrolled in an accelerated math pathway is independent of the student being a female.

Consider the following probabilities:

$P (F|A) = \farc{116}{170}\\\\P(A|F)=\frac{116}{1360}\\\\P(A)=\frac{170}{2468}\\\\P(F)=\frac{1360}{2468}$

If the two events are independent then:

P (F|A) = P(F)

P (A|F) = P (A)

But what would not be a valid comparison is:

P (A) = P(F)

Thus, the correct option is (c).

4 0

3 years ago

Find the rule and the graph of the function whose graph can be obtained by performing the translation 3 units left and 2 units d

Vsevolod [243]

Let

g(x)--------> the translation of the function f(x)

we know that

the rule of the translation is

$3$ units left and $2$ units down

that means

$(x,y)-------> (x-3,y-2)$

In the function f(x) the point $(0,0)$ is equal at the point $(-3,-2)$ in the function g(x)

therefore

the function g(x) is equal to

$g(x)=f(x+3)-2$

$g(x)=(x+3)^{3} -2$

<u>The answer is</u>

a) the rule of the translation is $(x,y)-------> (x-3,y-2)$

b) The graph in the attached figure

5 0

3 years ago