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frez [133]
3 years ago
7

Mrs. Robinson bought a novel at a bookstore on sale for 20% off its regular price of $29.99. Mr. Chang bought the same novel at

a different bookstore for 10% off its regular price of $25. Which person received the better discount . Explain
Mathematics
2 answers:
I am Lyosha [343]3 years ago
7 0

Answer:

Mr. Chang received the better discount

Step-by-step explanation:

Mrs. Robinson bought a novel at a bookstore on sale for 20% off its regular price of $29.99

The price of the novel at a bookstore = 29.99 -(20% × 29.99)

                                                              = 29.99 - (0.20 × 29.99)

                                                              = 29.99 - 5.998

                                                              = $23.99

Mr. Chang bought the same novel at a different bookstore for 10% off its regular price of $25.

The price of the novel at a different bookstore = 25 - (10% × 25)

                                                                              = 25 - (0.10 × 25)

                                                                              = 25 - 2.5

                                                                              = $22.50

Mr. Chang bought the novel at the price of $22.50 and Mrs. Robinson bought the same novel at the price of $23.99.

Therefore, Mr. Chang received the better discount.

Kay [80]3 years ago
4 0
Mr. Robinson gets $5.99 off which is $24.00
Mr. Chang gets $2.50 off which is $22.50

Work: 
29.99x.20=5.99     29.99-5.99 = 24.00
25.00x.10=2.50     25.00-2.50 = 22.50

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Answer:

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Step-by-step explanation:

Given the following :

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Obtain the Zscore for 90th percentile (0.90) on the z table = 1.28

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3 0
3 years ago
A family has three children.The oldest is 4 years older than the middle,and the youngest child is 2 years younger than the middl
lesantik [10]

Answer:

The age of the youngest child = x = 6 years

The age of middle child = y = 8 years

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Step-by-step explanation:

Let us represent:

The age of the youngest child = x

The age of middle child = y

The age of the oldest child = z

The sum of the ages of the children is 26.

Hence: x + y + z = 26...... Equation 1

The oldest is 4 years older than the middle

z = 4 + y

The youngest child is 2 years younger than the middle child

x = y - 2

Hence, we substitute 4 + y for z and y - 2 for x in Equation 1

x + y + z = 26...... Equation 1

y - 2 + y + 4 + y = 26

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Subtract 2 from both sides

3y + 2 - 2 = 26 - 2

3y = 26 - 2

3y = 24

y = 24/3

y = 8

Solving for x

x = y - 2

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x = 6

Solving for z

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z = 4 + 8

z = 12

Therefore:

The age of the youngest child = x = 6 years

The age of middle child = y = 8 years

The age of the oldest child = z = 12 years

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