Remember you can add like terms exg, 3y+4y=7y 3y^2+4y^2=7y^2, but cannot add 3y^2 and 4y, or 3 and 4y so
3a+2w-5a-9w
group like trems
3a-5a+2w-9w
subtract
-2a-7w
3y^2+2w^2-y^2-w^2
group like terms (think of w^2 and y^2 as 1w^2 and 1y^2)
3y^2-y^2+2w^2-w^2
subtract
2y^2+w^2
2x+2x=4x
<h2>
Greetings!</h2>
Answer:
3⋅(5⋅x)
5⋅(x⋅3)
15x
Step-by-step explanation:
As the values are inside the brackets, it does not matter what side the (x3) is on, so 3⋅(5⋅x) is equivalent.
Multiplying the contents of the brackets in the third one (x * 3) by 5 gives the same value as 3 * (x * 5) so 5⋅(x⋅3) is also equivalent.
On multiplying the brackets out:
5 * x = 5x
5x * 3 = 15x
So 15x is also equivalent.
<h2>Hope this helps!</h2>
Answer:
Time required by Ben was 12 minutes.
Step-by-step explanation:
Given:
Time Required for Fred = 16 mins
Ben completed his run in 3/4 of the amount of time of Freds run.
We need to find the time required by Ben.
Now Given that;
Ben completed his run in 3/4 of the amount of time of Freds run.
It means that time required by Ben is equal to 3/4 times time required by Fred.
Time required by Ben = 
Time required by Ben = 
Hence Time required by Ben was 12 minutes.
Hello from MrBillDoesMath!
Answer:
y = 2x - 3
Discussion:
2x - y = 3 => add "y" to both sides
2x - y + y = 3 + y => as -y+y = 0
2x = 3 + y => subtract 3 from each side of the equation
2x-3 = y
Thank you,
MrB
